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netineya [11]
3 years ago
14

What is the square root of 100

Mathematics
2 answers:
bekas [8.4K]3 years ago
4 0

Answer:

10

Step-by-step explanation:

laiz [17]3 years ago
4 0
The square root of 100 is 10
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<h3>y = 20</h3><h3 />

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180 - 90 + 10= 5y

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The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
Read 2 more answers
Given g(x)=8x+3 find the following g(-1) and g(2a+1)
Degger [83]

Answer:

g(-1) = -5

g(2a+1) = 16a+11

Step-by-step explanation:

Substitute the given value into the function and evaluate.

So for g(x) = 8x+3

You substitute g(-1)

So g(-1) = 8(-1)+3

That is how you get -5

Then g(2a+1)

So g(2a+1) = 8(2a+1)+3

Thats how you get 16a+11

Hope this helps. Mark as brainlist

4 0
2 years ago
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