What is the mean of these numbers? Round to the nearest tenth. 4, 2, 7, 5, 12, 7, 4, 11, 0

HELP PLEASE THE ANSWER Choice A. 192 ft B. 96 ft C. 247 ft D. 302 ft

vfiekz [6]

The answer is B.

Hope this helps good luck

6 0

3 years ago

he amount of money left in Alma’s bank account is expressed by the linear equation y = -27x + 577, where x represents the number

kow [346]

Answer:

After 16 weeks she will have 145 dollars left in her account.

Step-by-step explanation:

since 145 represents the amount of money in her account we will substitute that for "y" and solve for "x"

145=-27x+577

145-577=-27x

-432=-27x

-432/-27= -27x/-27

16=x

3 0

4 years ago

Is 9,440,260 divisible by 3? YES or NO HELP ME PLZ!!!

mina [271]

Answer:

Yes It is Divisible by 3

Step-by-step explanation:

It is 314 in whole numbers but it has some decimals.

6 0

3 years ago

Read 2 more answers

If Triangle Q S R is congruent to triangle Y X Z describes two triangles, which other statement is also true?

Soloha48 [4]

Answer:

The second one because q goes with y r goes with z and s goes with x

Step-by-step explanation:

5 0

3 years ago

Gummy bears: red or yellow? Chance (Winter 2010) presented a lesson in hypothesis testing carried out by medical students in a b

xxMikexx [17]

Answer:

$z=\frac{0.802 -0.5}{\sqrt{\frac{0.5(1-0.5)}{121}}}=6.64$

$p_v =2*P(z>6.64)=3.14x10^{-11}$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of students who will correctly identify the color is different than 0.5

Step-by-step explanation:

Data given and notation

n=121 represent the random sample taken

X=97 represent the people who identify the color of the gummy bear

$\hat p=\frac{97}{121}=0.802$ estimated proportion of people who identify the color of the gummy bear

$p_o=0.5$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Part a

For this case the parameter that we want to test is 0.5 for the proportion of the population of students will correctly identify the color

Part b: Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that there is no relationship between color and gummy bear flavor (population proportion different from 0.5).:

Null hypothesis: $p=0.5$

Alternative hypothesis: $p \neq 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part c: Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.802 -0.5}{\sqrt{\frac{0.5(1-0.5)}{121}}}=6.64$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =2*P(z>6.64)=3.14x10^{-11}$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of students who will correctly identify the color is different than 0.5

8 0

4 years ago