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Serggg [28]
2 years ago
12

Help me pleasee. Solve the system by substitution

Mathematics
1 answer:
saveliy_v [14]2 years ago
5 0

Answer:

(3, - 2 )

Step-by-step explanation:

Given the 2 equations

4x - 2y = 16 → (1)

y = - 5x + 13 → (2)

Substitute y = - 5x + 13 into (1)

4x - 2(- 5x + 13) = 16 ← distribute and simplify left side

4x + 10x - 26 = 16

14x - 26 = 16 ( add 26 to both sides )

14x = 42 ( divide both sides by 14 )

x = 3

Substitute x = 3 into (2) for corresponding value of y

y = - 5(3) + 13 = - 15 + 13 = - 2

solution is (3, - 2 )

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Right triangle ABC has three sides with lengths AB= 119, BC = 169, CA= 120. Find the value of cos C. hint: draw and label the tr
GenaCL600 [577]

Answer:

\cos(C)=\frac{120}{169}

Step-by-step explanation:

The triangle is shown in the attachment.

Recall that;

\cos(C)=\frac{Adjacent}{Hypotenuse}

This implies that;

\cos(C)=\frac{|AC|}{|BC|}

We substitute the values into the ratio to obtain

\cos(C)=\frac{120}{169}


8 0
3 years ago
Can somebody help me with this problem. Like asap
denis-greek [22]

Answer:

asap

Step-by-step explanation:

6 0
3 years ago
Which of the following is the surface area of the right cylinder below?
yarga [219]

Answer:

if it is TSA- 396 or 395.64

if it is CSA- 88 or 87.92

Step-by-step explanation:

r=7

h=2

TSA= 2 pi r(r+h)

=2*22/7*7*9= 396

<em>CSA</em>= 2 pi r h

2*22/7*7*2=88

when you use pi as 3.14 instead of 22/7 you get the answer with the decimal symbol.. in such case the TSA would be 395.64 and CSA would be 87.92

6 0
3 years ago
Read 2 more answers
What is the length of BC⎯⎯⎯⎯⎯ ?<br><br><br> Enter your answer in the box.
Rudiy27

Answer:

  \overline{\text{BC}}=\boxed{22}

Step-by-step explanation:

The angle marks mean those angles have the same measure. That means the sides opposite them have the same measure, so ...

  2x -24 = x -2

  x = 22 . . . . . . . . . add 24-x

The length of BC is x, so is 22.

BC = 22

8 0
3 years ago
Solve the system of linear equations.
sweet-ann [11.9K]

Answer:

  • dependent system
  • x = 2 -a
  • y = 1 +a
  • z = a

Step-by-step explanation:

Let's solve this by eliminating z, then we'll go from there.

Add 6 times the second equation to the first.

  (3x -3y +6z) +6(x +2y -z) = (3) +6(4)

  9x +9y = 27 . . . simplify

  x + y = 3 . . . . . . divide by 9 [eq4]

Add 13 times the second equation to the third.

  (5x -8y +13z) +13(x +2y -z) = (2) +13(4)

  18x +18y = 54

  x + y = 3 . . . . . . divide by 18 [eq5]

Equations [eq4] and [eq5] are identical. This tells us the system is dependent, and has an infinite number of solutions. We can find them in terms of z:

  y = 3 -x . . . . solve eq5 for y

  x +2(3 -x) -z = 4 . . . . substitute into the second equation

  -x +6 -z = 4

  x = 2 - z . . . . . . add x-4

  y = 3 -(2 -z)

  y = z +1

So far, we have written the solutions in terms of z. If we use the parameter "a", we can write the solutions as ...

  x = 2 -a

  y = 1 +a

  z = a

_____

<em>Check</em>

First equation:

  3(2-a) -3(a+1) +6a = 3

  6 -3a -3a -3 +6a = 3 . . . true

Second equation:

  (2-a) +2(a+1) -a = 4

  2 -a +2a +2 -a = 4 . . . true

Third equation:

  5(2-a) -8(a+1) +13a = 2

  10 -5a -8a -8 +13a = 2 . . . true

Our solution checks algebraically.

6 0
3 years ago
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