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statuscvo [17]
3 years ago
6

What number between 250 and 260 that is divisible by 9

Mathematics
1 answer:
butalik [34]3 years ago
3 0
28 I feel lucky. Let me know.
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5(x – 4) + 3x – 9x = 6 - (2x + 5) + 8x
AURORKA [14]
This is what i got:
-x-20=6x+1
6 0
3 years ago
Geometry help please!!!
julia-pushkina [17]
Before we begin, let's identify what kind of angles these are and are they related in any way?

These angles are both acute and they are both corresponding angles.
Corresponding angles are equal to each other, and we can use this fact to our advantage.

Since they are equal to each other, we can set the equations of 1 and 2 equal to each other. Like so,

1 = 2
83 - 2x = 92 - 3x

Now, we can solve for X by isolating it on one side.

83 - 2x = 92 - 3x

Add 3x to each side: (This basically moves the X on the right side to the left.)
83 - 2x + 3x = 92 - 3x + 3x
83 + x = 92

Subtract 83 on each side to isolate the X.
83 + x - 83 = 92 - 83 
x = 92 - 83
x = 9

Therefore, X equals 9. To check our work, we can substitute X for 9.
83 - 2(9) = 92 - 3(9)
83 - 18 = 92 - 27
65 = 65  - 
TRUE

So to conclude, Angle 1 is 65 degrees, Angle 2 is 65 degrees, and X equals 9.

Hope I could help you out!
If my answer is incorrect, or I provided an answer you were not looking for, please let me know. However, if my answer is explained well and correct, please consider marking my answer as Brainliest!  :)

Have a good one.
God bless!
7 0
3 years ago
6 sin _ _ 3 csc _ = 0
mamaluj [8]
6 sin θ - 3 csc θ = 0
6 sin θ = 3 csc θ = 3/sin θ
6 sin^2 θ = 3
sin^2 θ = 3/6 = 1/2
sin θ = sqrt(1/2)
θ = arcsin(sqrt(1/2)) = 45 degrees.
θ = 45°
6 0
2 years ago
What is the radical expression
Margaret [11]

5x^{\frac{1}{4} }=5\cdot x^{\frac{1}{4}}= 5\sqrt[4]{x} \\\\because\\\\a^{\frac{1}{n} }=\sqrt[n]{a}

6 0
3 years ago
Which is an x-intercept of the continuous function in the
Paladinen [302]

Answer:

(-1, 0), (2, 0), (3, 0)

Step-by-step explanation:

x-intercept of a line is defined by a point where y = 0.

So the point in the form of (x, 0) will be the x-intercept of the given continuous function.

From the table attached,

For x = -1, f(-1) = 0

For x = 2, f(2) = 0

For x = 3, f(3) = 0

Points (-1, 0), (2, 0) and (3, 0) are the x-intercepts of the continuous function f(x).

5 0
3 years ago
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