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statuscvo [17]
3 years ago
6

What number between 250 and 260 that is divisible by 9

Mathematics
1 answer:
butalik [34]3 years ago
3 0
28 I feel lucky. Let me know.
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Please help ASAP!!! I will mark the Brainliest!!
Svetlanka [38]
To answer this question, you need to know that a scale factor is the relationship between one dimension of the shape.  

Because the information given to us is a two-dimensional measurement, you will need to consider that when getting the answer.

The ratios of the areas of the  triangles is 3/5 x 3/5 or 9/25.

To determine the area of the larger triangle, you will solve the following equation using the information you know.  x is the area of the larger triangle.

9/25x = 576; solve for x by dividing both sides by 9/25
x = 1600 square inches

The area of the larger triangle is 1600 square inches.
6 0
3 years ago
-10w + 12 = -9w + 13<br> What value of w makes the equation true?
nika2105 [10]
W=-15 I hope this helped.
6 0
3 years ago
Why does: 5x+3x+2x = 10x and not 10xxx?
Helen [10]
Because you are not adding the x's .When you add the coefficients, the variable comes along with it.
8 0
3 years ago
Read 2 more answers
Cameron said that the Y intercept of a quadratic function always tells the maximum value of the function. explain Cameron's erro
Leno4ka [110]

Answer:

We can have two cases.

A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.

A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.

Where for a generic function:

y(x) = a*x^2 + b*x + c

The vertex is at:

x = -a/2b

and the maximum value is:

y(-a/2b)

4 0
3 years ago
Can someone please help me its urgent!!!!!!!!!!<br> 3x + 11 = 3x - 11
user100 [1]

Answer:

\Large\boxed{\mathsf{\Rightarrow NO\quad SOLUTIONS}}

Step-by-step explanation:

<h3><u>TO SOLVE:</u></h3>

Isolate by the x on one side of the equation.

<h3><u>SOLUTIONS:</u></h3>

First, subtract 3x from both sides.

\displaystyle \Rightarrow \mathsf{3x+11-3x=3x-11-3x}}

Solve.

\displaystyle \mathsf{11=-11}

Sides are NOT equal.

\Large\boxed{\mathsf{\Rightarrow THERE \quad ARE \quad NO \quad SOLUTIONS}}}

Therefore, there are no solutions.

6 0
3 years ago
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