Answer:
Step-by-step explanation:
Given:
x = 2cost,
t = (1/2)arccosx
y = 2sint
dy/dx = dy/dt . dt/dx
dy/dt = 2cost
dt/dx = -1/√(1 - x²)
dy/dx = -2cost/√(1 - x²)
Differentiate again to obtain d²y/dx²
d²y/dx² = 2sint/√(1 - x²) - 2xcost/(1 - x²)^(-3/2)
At t = π/4, we have
(√2)/√(1 - x²) - (√2)x(1 - x²)^(3/2)
Answer:
total ground and wall angle is 90°
beam angle with ground= 51
beam angle with wall =39
because total angle=angle with ground + angle with wall
angle with wall=total angle-angle with ground
angle with wall= 90-51=39
the answer would be 67,127 because the number in the ones would be 7 and the tens number would be 2 since it wouldn't more than 1.
67,102
67,135
1-7
67,127
Answer:
![\large\boxed{x=-2\ or\ x=-\dfrac{1}{3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bx%3D-2%5C%20or%5C%20x%3D-%5Cdfrac%7B1%7D%7B3%7D%7D)
Step-by-step explanation:
The quadratic formula of a quadratic equation
![ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0%5C%5C%5C%5Cx%3D%5Cdfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
We have the equation:
![3p^2+7p+2=0\to a=3,\ b=7,\ c=2](https://tex.z-dn.net/?f=3p%5E2%2B7p%2B2%3D0%5Cto%20a%3D3%2C%5C%20b%3D7%2C%5C%20c%3D2)
Substitute:
![b^2-4ac=7^2-4(3)(2)=49-24=25\\\\\sqrt{b^2-4ac}=\sqrt{25}=5\\\\x_1=\dfrac{-7-5}{2(3)}=\dfrac{-12}{6}=-2\\\\x_2=\dfrac{-7+5}{2(3)}=\dfrac{-2}{6}=-\dfrac{1}{3}](https://tex.z-dn.net/?f=b%5E2-4ac%3D7%5E2-4%283%29%282%29%3D49-24%3D25%5C%5C%5C%5C%5Csqrt%7Bb%5E2-4ac%7D%3D%5Csqrt%7B25%7D%3D5%5C%5C%5C%5Cx_1%3D%5Cdfrac%7B-7-5%7D%7B2%283%29%7D%3D%5Cdfrac%7B-12%7D%7B6%7D%3D-2%5C%5C%5C%5Cx_2%3D%5Cdfrac%7B-7%2B5%7D%7B2%283%29%7D%3D%5Cdfrac%7B-2%7D%7B6%7D%3D-%5Cdfrac%7B1%7D%7B3%7D)
Answer:
-9
Step-by-step explanation:
36 ÷ (1 - |2 - 7|) =
Start with the calculation inside the absolute value.
= 36 ÷ (1 - |-5|)
Now take the absolute value of -5 which is 5.
= 36 ÷ (1 - 5)
Do the operation inside the parentheses, 1 - 5 = -4.
= 36 ÷ (-4)
Finally divide. Remember that positive divided by negative is negative.
= -9