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o-na [289]
3 years ago
6

How do you fine arccot(-sqrt(3))?

Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0

Answer:The answer is be And i’m Strongly positive about this because i just got it right!

Step-by-step explanation:

hjlf3 years ago
7 0
arccot{(- \sqrt{3}) }=arccot(-\cot{ \frac{\pi}{6} )=-arccot{(\cot{ \frac{\pi}{6})}=- \frac{\pi}{6}
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6 percent was spent
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3 years ago
The enrollment for a new program is 1,500 students. the program is expected to grow at a rate of 0.03. what is the expected enro
Hatshy [7]

The expected enrolment in 7 years is  1845.

<h3>What is the expected enrolment?
</h3>

The formula for calculating future value of the number of students is an exponential equation with this form:

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To learn more about future value, please check: brainly.com/question/18760477

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2 years ago
Find the area of the irregular figure. I don’t know this I need help.
Shkiper50 [21]

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4 0
3 years ago
A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An
Gnom [1K]
I would solve this using tangents.  Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
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Now write the tangent ratios:
tan A = \frac{h+70}{40}  , tan B = \frac{70}{40}

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
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Plug in what we know:
tan(9) = \frac{ \frac{h+70}{40} -  \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}
tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}
h = \frac{650 tan(9)}{4-7 tan(9)}
h = 35.6
7 0
3 years ago
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