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o-na [289]
3 years ago
6

How do you fine arccot(-sqrt(3))?

Mathematics
2 answers:
Rus_ich [418]3 years ago
8 0

Answer:The answer is be And i’m Strongly positive about this because i just got it right!

Step-by-step explanation:

hjlf3 years ago
7 0
arccot{(- \sqrt{3}) }=arccot(-\cot{ \frac{\pi}{6} )=-arccot{(\cot{ \frac{\pi}{6})}=- \frac{\pi}{6}
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3 years ago
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4|n|-5=7 please help me solve
DedPeter [7]
I think you meant to type

4(n)-5=7.

4n = 7 + 5

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A-Town wants to know the number of cell phones in each household the town divides the population up by neighborhood and surveys
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A rain gutter is made from sheets of aluminum that are 16 inches wide by turning up the edges to form right angles. Determine th
blsea [12.9K]

Answer:

Depth of the rain gutter is 8 inches

Step-by-step explanation:

Let’s assume ‘x’ is the depth of the rain gutter

Then the width of the rain gutter can be written as 16 - 2x

Cross sectional area

A = depth x width

Substitute values

A = x*(16 - 2x)

A = 16x – 2x^2

Now according to axis of symmetry for maximum area x = -b/2a

x = -16/2*(-2)

x = 4 inches depth of rain gutter, substitute the value of x to get

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Area of the rain gutter for maximum water flow

A = 4 * 8

A = 32 square inch.

8 0
3 years ago
The area of a trapezoid is 864cm². It has a height of 24 cm, and the length of one of its bases is 30 cm. What is the length of
Amiraneli [1.4K]

The area <em>A</em> of a trapezoid with height <em>h</em> and bases <em>b</em>₁ and <em>b</em>₂ is equal to the average of the bases times the height:

<em>A</em> = (<em>b</em>₁ + <em>b</em>₂) <em>h</em> / 2

We're given <em>A</em> = 864, <em>h</em> = 24, and one of the bases has length 30, so

864 = (<em>b</em>₁ + 30) 24 / 2

864 = (<em>b</em>₁ + 30) 12

864 = (<em>b</em>₁ + 30) 12

72 = <em>b</em>₁ + 30

<em>b</em>₁ = 42

5 0
3 years ago
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