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Varvara68 [4.7K]
3 years ago
12

A^3+2abc-5c^2 a=3 b=7 c=-3

Mathematics
2 answers:
Ede4ka [16]3 years ago
5 0

Answer:

-144

Step-by-step explanation:

a³ + 2abc - 5c² = (3)³ + 2(3)(7)(-3) - 5(-3)²

= 3³ + (-126) - 5(-3)²

= 27 + (-126) - 45

= (-99) - 45

= -144

your welcome

kondor19780726 [428]3 years ago
3 0

Answer:

3^3+2(3)(7)(-3)-5(-3)^2=-144

hope this is your required answer

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FinnZ [79.3K]

If the ball was thrown straight up at 24 ft/sec when it was 5 ft above the ground, the ball reached a maximum height of 7.25 m

\texttt{ }

<h3>Further explanation</h3>

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

<h2>D = b² - 4 a c</h2>

From the value of Discriminant , we know how many solutions the equation has by condition :

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D = 0 → One Real Root

D > 0 → Two Real Roots

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An axis of symmetry of quadratic equation y = ax² + bx + c is :

\large {\boxed {x = \frac{-b}{2a} } }

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

p(t) = 3gt^2 + v_ot + p_o

p(t) = 3(-32)t^2 + 24t + 5

p(t) = -64t^2 + 24t + 5

<u>Asked:</u>

p_{max} = ?

<u>Solution:</u>

<em>At the maximum height , velocity is 0 m/s:</em>

v = \frac{dp(t)}{dt}

v = \frac{d}{dt} ( -64t^2 + 24t + 5 )

v = (-64)(2)t^{2-1} + 24

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t = 0.1875 \texttt{ s}

\texttt{ }

p(t) = -64t^2 + 24t + 5

p(0.1875) = -64(0.1875)^2 + 24(0.1875) + 5

p(0.1875) = 7.25 \texttt{ m}

\texttt{ }

<h3>Learn more</h3>
  • Solving Quadratic Equations by Factoring : brainly.com/question/12182022
  • Determine the Discriminant : brainly.com/question/4600943
  • Formula of Quadratic Equations : brainly.com/question/3776858

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

\texttt{ }

Keywords: Quadratic , Equation , Discriminant , Real , Number

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