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Dafna11 [192]
4 years ago
15

Simplify 3-(4x-5)+6.

Mathematics
2 answers:
Leviafan [203]4 years ago
6 0
3 + -4x = 5(x +6)

Re-order the terms:

3 + -4x = 5(6 + x)
3 + -4x = (6 . 5 + x . 5)
3 + -4x = (30 + 5x)

Solving:

3 + -4x = 30 + 5x

Solving for variable "x"

Move all terms containing "x" to the left, all the other terms to the right.

Add "-5x" to each side of the equation.
3 + -4x + -5x = 30 + 5x + -5x

Combine like terms: 
-4x + -5x = -9x
3 + -9x = 30 +5x + -5x

Combine like terms: 
5x + -5x = 0
0 + -9x = 30 +0
3 + -9x = 30

Add "-3" to each side of the equation.
3 + -3 + -9x = 30 + 3

Combine like terms: 
3 + -3 = 0
0 + -9x = 30 + -3
-9x = 30 + -3

Combine like terms: 
30 + -3 = 27
-9x = 27

Divide each side by "-9".
x = -3

Simplifying:
x = -3










zmey [24]4 years ago
3 0

3−(4x−5)+6

=3+−4x+5+6

=3+−4x+5+6

=(−4x)+(3+5+6)

=−4x+14

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SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

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