<span>The answer is Gaseous metals</span>
Two Half Cell reactions are as,
Reduction: PbO₂ + 2e⁻ → Pb²⁺
As it is acidic medium reaction, so add H⁺ on reactant side as it has more number of oxygen atoms and add H₂O on product side, and balance tehe elements, So,
4 H⁺ + PbO₂ + 2e⁻ → Pb²⁺ + 2 H₂O (1)
Oxidation: I⁻ → I₂ + 1e⁻
Balance Number of elements along with electrons,
2 I⁻ → I₂ + 2e⁻ (2)
Compare eq. 1 and 2,
4 H⁺ + PbO₂ + 2e⁻ → Pb²⁺ + 2 H₂O
2 I⁻ → I₂ + 2e⁻
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
PbO₂ + 2 I⁻ + 4 H⁺ → Pb²⁺ + I₂ + 2H₂O
Number of Coefficients = 11
Answer:
1
Explanation:
The empirical formula describes the simplest whole number ratio of each type of atom in a compound. To find this formula, you need to (1) convert grams of each element to moles (via their atomic masses) and then (2) find the ratio of each element (by dividing each molar value by the smallest mole value).
(Step 1)
Atomic Mass (Zn): 65.380 g/mol
Atomic Mass (C): 12.011 g/mol
Atomic Mass (O): 15.998 g/mol
10.40 grams Zn 1 mole
------------------------ x ------------------------ = 0.159 moles Zn
65.380 grams
1.92 grams C 1 mole
--------------------- x ----------------------- = 0.160 moles C
12.011 grams
7.68 grams O 1 mole
---------------------- x ------------------------ = 0.480 moles O
15.998 grams
(Step 2)
0.159 moles Zn / 0.159 = 1 atom Zn
0.160 moles C / 0.159 = 1 atom C
0.480 moles O / 0.159 = 3 atom O
The empirical formula is Zn₁C₁O₃. Therefore, the value that should be in the space is 1.
6CO2 + 6H2O → C6H12O6 + 6O2.
Answer:
t = 2 seconds
Explanation:
It is given that,
Mass of a boy, m = 50 kg
Initial speed of boy, u = 0
Final speed of boy, v = 8 m/s
Force exerting by another boy, F = 200 N
Let t is the time of contact. The force acting on an object is given by :
F = ma
a is acceleration
So,
So, the contact time is 2 seconds.
