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3 years ago

. Using the pH scale below what would be the pH value of an Acid? *

Chemistry

1 answer:

earnstyle [38]3 years ago

6 0

Answer : The pH value of an acid is below 7.

Explanation :

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

Mathematically,

$pH=-\log [H^+]$

When the pH less than 7 then the solution is acidic and the concentration of hydrogen ion is greater than hydroxide ion.

When the pH more than 7 then the solution is basic and the concentration of hydrogen ion is less than hydroxide ion.

When the pH is equal to 7 then the solution is neutral and the concentration of hydrogen ion is equal to the hydroxide ion.

Hence, the pH value of an acid is below 7.

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Which is not an indicator for a chemical change?

Anastasy [175]

Answer:

Explanation:

Because it does not change entirely.

8 0

3 years ago

Calculate the percentage by mass of cerium in cerium carbonate

levacccp [35]

Answer:

60.88%

Explanation:

The formula for cerium carbonate is Ce₂(CO₃)₃.

Let's assume we have 1 mol of cerium carbonate. The total mass would be equal to the molar mass of Ce₂(CO₃)₃, 460.25 g/mol.

Out of those 460.25 g, the mass corresponding to cerium would be:

2 * Molar mass of Ce = 2 * 140.11 g/mol = 280.22 g

Now we can calculate the percentage by mass of cerium:

% mass = 280.22 / 460.25 * 100% = 60.88%

5 0

2 years ago

Do you know any of these?

jok3333 [9.3K]

Mass can identify molecules and atoms

3 0

3 years ago

A 1.638 Gram pure sample of a compound containing only carbon hydrogen and oxygen was burned in excess oxygen gas 3.117 g of car

andrew11 [14]

Answer:

C2H6O

Explanation:

First, find the masses of C, H, and O. I used ratios.

3.117g CO2 x 1 mol CO2/44.01g CO2 x 1 mol C/1 mol CO2 x 12.01g C/1 mol C = 0.850606 g C

1.911g H2O x 1 mol H2O/18.016g H2O x 2 mol H2O/1 mol H2O x 1.008g H/1 mol H = 0.213842 g H

To find the mass of oxygen, just add the masses of C and H together and subtract that from the total mass of the sample.

1.638 - (0.850606 + 0.213842) = 0.57355 g O

Second, find the moles of C, H, and O.

0.850606g C x 1 mol C/12.01g C = 0.070825 mol C

0.213842g H x 1 mol H/1.008g H = 0.212145 mol H

0.57355 g O x 1 mol O/16g O = 0.035847 mol O

Finally, divide the number of moles of each element by the smallest value of moles calculated. In this case, the smallest value is 0.035847.

0.070825/0.035847 = 2

0.212145/0.035847 = 6

0.035847/0.035847 = 1

7 0

3 years ago

When rubidium metal is exposed to air, two atoms of rubidium, Rb, combine with one atom

Eddi Din [679]

2.1653 g

Explanation:

The molar mass of Rubidium is;

85.468 g/mol

Therefore the moles of Rubidium that reacted with oxygen is;

1.98 / 85.468

= 0.0232 moles

If every two moles of Rubidium reacts with one mole of oxygen then the amount of oxygen consumed in the chemical reaction is;

0.5 * 0.0232

= 0.0116 moles

The molar mass of an oxygen atom is 16 g/mole. Then the amount of O in grams consumed is;

0.0116 * 16

=0.1853 g

The final weight of the Rubidium II Oxide is;

1.98 + 0.1853

= 2.1653 g

8 0

3 years ago