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3 years ago

A balloon occupies 175 cm at 25.0 C. What volume will it occupy at 42.5 °C?

Chemistry

1 answer:

patriot [66]3 years ago

4 0

175 cm³ instead of 175 cm.

Answer:

297.5 cm³

Explanation:

From the question;

Initial volume; V1 = 175 cm³

Initial temperature; T1 = 25°C

Final temperature; T2 = 42.5°C

From Charles law we can find the volume V2 from the equation;

V1/T1 = V2/T2

Making V2 the subject gives;

V2 = V1 × T2/T1

V2 = (175 × 42.5)/25

V2 = 297.5 cm³

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Hypoventilation can cause oxygen levels to fall too low, a condition called . carbon dioxide levels may rise too high, a conditi

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1 year ago

Examine the reaction equation. Mg(OH)2(s) + HCl(aq) →H2O(l) + MgCl2(aq) What coefficients will balance the equation? A) 2, 4, 2,

r-ruslan [8.4K]

Answer:

Explanation:

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6 0

3 years ago

Read 2 more answers

The rate constant k for a certain reaction is measured at two different temperatures temperature 376.0 °c 4.8 x 108 280.0 °C 2.3

9966 [12]

Answer:

The activation energy for this reaction = 23 kJ/mol.

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Where,

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314×10⁻³ kJ / K mol

$k_2=2.3\times 10^8$

$T_2=280\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (280 + 273.15) K = 553.15 K

$T_2=553.15\ K$

$k_1=4.8\times 10^8$

$T_1=376\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (376 + 273.15) K = 649.15 K

$T_1=649.15\ K$

So,

$\left(\ln \left(\:\frac{4.8\times \:\:\:10^8}{2.3\times \:\:\:10^8}\right)\right)\:=-\frac{E_a}{8.314\times \:10^{-3}\ kJ/mol.K}\times \:\left(\frac{1}{649.15\ K}-\frac{1}{553.15\ K}\right)$

$E_a=-\frac{10^{-3}\times \:8.314\ln \left(\frac{10^8\times \:4.8}{10^8\times \:2.3}\right)}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=-\frac{\frac{8.314\ln \left(\frac{4.8}{2.3}\right)}{1000}}{-\frac{96}{359077.3225}}\ kJ/mol$

$E_a=22.87\ kJ/mol$

The activation energy for this reaction = 23 kJ/mol.

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3 years ago

What letter represents the activation energy for the reverse reaction?

Bezzdna [24]

Answer: The correct answer is Option 4: U

Explanation:

Activation energy is defined as the energy that is given to a chemical system with potential reactants to produce products. It is represented as $E_{ac}$

It is represented as the energy from the reactants to the activated complex.

Reverse reaction is defined as the reaction in which the products formed become reactants and leads to the formation of reactants back.

So, here, the activation energy of the reverse reaction is the energy between the products and the activated complex, which is represented as letter U in the given graph.

Hence, the correct answer is Option 4: U

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3 years ago

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