What is the pH of a solution formed at the neutralization point by the reaction of 25.0 mL of 0.180 molar acetic acid (Ka = 1.8
1 answer:
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Answer:
<h2>7.54 atm </h2>Explanation:
The required pressure can be found by using the formula for Boyle's law which is
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
From the question we have
We have the final answer as
<h3>7.54 atm </h3>Hope this helps you
18)
a. Ra
d. Ag
19)
a. C
b. Br
c. Mg
20)
a. S
b. Br
c. O
Sorry wasn’t sure about some of them in #18
Hope the notes are helpful.
a. Ra
d. Ag
19)
a. C
b. Br
c. Mg
20)
a. S
b. Br
c. O
Sorry wasn’t sure about some of them in #18
Hope the notes are helpful.
Answer= 2 mol/dm^3
Explanation:-
Firstly, we convert the volume, which is in cm^3 to dm^3. To do that divide number in cm^3 by 1000:
100/1000= 0.1 dm^3
Formula for concentration is:
Concentration= No. of moles/ Volume
So,
Concentration= 0.2/0.1
Answer= 2 mol/dm^3
Explanation:-
Firstly, we convert the volume, which is in cm^3 to dm^3. To do that divide number in cm^3 by 1000:
100/1000= 0.1 dm^3
Formula for concentration is:
Concentration= No. of moles/ Volume
So,
Concentration= 0.2/0.1
Answer= 2 mol/dm^3