Answer:
The two-way table is attached.
Step-by-step explanation:
The activities are listed as columns, with an additional column for totals. The genders are listed as rows, with an additional row for totals.
It seems the first line has to be
1. AB=CD and AD=CB 1. given
2. AC=AC 2. Reflexivity (things are equal to themselves)
3
ACB
CAD 3. SSS
4.
1 =
4. Corresponding parts of congruent triangles
5 DC || AB 5. Congruent alternate traversal angles imply parallel lines
Answer: (-4,-6) is the point that ALMOST satisfies both inequalities. IF they were equalities, this would be the solution.
The question is a bit confusing as it asks for "which points (x,y) satisfies both" It's ungrammatical, and many points (infinite within the shaded region) are solutions that SATISFY the system of inequalities!
Step-by-step explanation: Substitute the x and y-values and see if the inequalities are true.
y>x-2 -6> -4-2 -6= -6
That point (-4,-6) is on the dashed line, so not exactly a true solution; this is a question about inequalities. So y values have to be greater than-6 or x-values less than -4 for a true inequality.
y>2x+2
-6>(2)(-4) +2
-6> -8 +2
-6> -6 Again, equal, so for this y-values have to be greater than-6 and/or x-values less than -4 in order to have a true inequality.
If you have the graph to look at, you can select any points in the shaded region that satisfies both of the inequalities.
You answer is A. You have to substitute the values of x and y into the equation.
(3*1)= 4-1
4-(2*1)=2
(4,1)
(x,y)
