we are given
where
F is the number of board feet
d is the diameter (in inches) of the log
Since, we have to minimize F
so, firstly we will find it's derivative
now, we can set it to 0
and then we can solve for d
so, we get diameter as
..............Answer
Answer:
2/17
Step-by-step explanation:
Add all the marbles and add the 2 in front because 2 is what you are taking, and 17 is the total of marbles.
Step One
Find the area of the rectangle
Area = L * W
Area = 89 cm * 70 cm
Area = 6230 cm^2
Step Two
What is the formula for the two end semicircles?
Two semicircles = 1 whole circle
Area of any circle = pi * r^2
Step Three
Find the area of the circle
r = the width / 2 This may not be true. You need the diagram. If the circles are drawn on the length then use r = the length / 2
r = 70/2 = 35 cm
Area of circle = pi * r^2
Area of circle = 3.14 * 35^2
Area of circle = 3846.5
Step Four
Find the total area
The total area = Area of the rectangle + area of circle
The total area = 6230 + 3846.5
The total area = 10076.5 cm^2 <<<< Answer
Answer:
The prices at which manager predict that at least 55 hats will be sold would be would be of $38
Step-by-step explanation:
According to the given data we the following:
Number of hats sold at $18=115
The manager predicts at 3 less will sold for every rise in 1 $ for at least 55 hats.
Therefore, reduction in number=115 hats-55 hats=60
So, increase in price=reduction in number/number of hats manager predicts that will be sold for every $1 increase in price
increase in price=60/3=$20
Therefore, prices at which manager predict that at least 55 hats will be sold would be=$18+$20=$38
The prices at which manager predict that at least 55 hats will be sold would be would be of $38
Answer:
Hello,
Step-by-step explanation:
![A=(1,2)\\B=(0,-1)\\\overrightarrow{AB}=((0,-1)-(1,2)=(-1,-3)\ ||\overrightarrow{AB}||^2=1+9=10\\\overrightarrow{BC}=((3,-2)-(0,-1)=(3,-1)\ ||\overrightarrow{BC}||^2=9+1=10\\\\Triangle\ is\ isosceles.\\\\\overrightarrow{AB}.\overrightarrow{BC}=(-1,-3)*\left[\begin{array}{c}3\\-1\end{array}\right] =-3+3=0\\\\Triangle \ is\ right.\\\\](https://tex.z-dn.net/?f=A%3D%281%2C2%29%5C%5CB%3D%280%2C-1%29%5C%5C%5Coverrightarrow%7BAB%7D%3D%28%280%2C-1%29-%281%2C2%29%3D%28-1%2C-3%29%5C%20%7C%7C%5Coverrightarrow%7BAB%7D%7C%7C%5E2%3D1%2B9%3D10%5C%5C%5Coverrightarrow%7BBC%7D%3D%28%283%2C-2%29-%280%2C-1%29%3D%283%2C-1%29%5C%20%7C%7C%5Coverrightarrow%7BBC%7D%7C%7C%5E2%3D9%2B1%3D10%5C%5C%5C%5CTriangle%5C%20is%5C%20isosceles.%5C%5C%5C%5C%5Coverrightarrow%7BAB%7D.%5Coverrightarrow%7BBC%7D%3D%28-1%2C-3%29%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D3%5C%5C-1%5Cend%7Barray%7D%5Cright%5D%20%3D-3%2B3%3D0%5C%5C%5C%5CTriangle%20%5C%20is%5C%20right.%5C%5C%5C%5C)
