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djyliett [7]
3 years ago
14

Nadine wants to convince her school to provide the students with an extra playground.

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
8 0

Answer:

The school would have to give $300 and each side would be 100cm

Step-by-step explanation:

(4x - 8)cm = Side length

Solve for X

3(4x - 8) = 300

(Getting rid of the three)

(12x -24) = 300  

(Getting rid of the 24)

(12x) = 324

(Getting rid of the 12)

(12x/12) = 324/12

X = 27

27 x 4

Side length = (108 - 8)

108 - 8 = 100cm

100 x 3 = 300cm (1cm = $1)

$300

Each Side would be 100cm

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3 years ago
If M is the centroid of triangle GHI, HL=45, JI=63, and KG=60, find the missing measures
AysviL [449]

Answer:

Part a) ML=15\ units

Part b) HM=30\ units

Part c) JM=21\ units

Part d) MI=42\ units

Part e) GM=40\ units

Part f) MK=20\ units

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

A <u><em>centroid</em></u> of a triangle is the point where the three medians of the triangle meet. A median of a triangle is a line segment from one vertex to the mid point on the opposite side of the triangle.

The centroid is located two thirds of the distance from any vertex of the triangle

Part a) Find ML

we have

HL=45\ units

we know that

ML=\frac{1}{3}HL

substitute the given value

ML=\frac{1}{3}(45)

ML=15\ units

Part b) Find HM

we have

HL=45\ units

we know that

HM=\frac{2}{3}HL

substitute the given value

HM=\frac{2}{3}(45)

HM=30\ units

Part c) Find JM

we have

JI=63\ units

we know that

JM=\frac{1}{3}JI

substitute the given value

JM=\frac{1}{3}(63)

JM=21\ units

Part d) Find MI

we have

JI=63\ units

we know that

MI=\frac{2}{3}JI

substitute the given value

MI=\frac{2}{3}(63)

MI=42\ units

Part e) Find GM

we have

KG=60\ units

we know that

GM=\frac{2}{3}KG

substitute the given value

GM=\frac{2}{3}(60)

GM=40\ units

Part f) Find MK

we have

KG=60\ units

we know that

MK=\frac{1}{3}KG

substitute the given value

MK=\frac{1}{3}(60)

MK=20\ units

6 0
4 years ago
Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same poi
skelet666 [1.2K]

Answer:

Alan: 200 m/min

Brian: 150 m/min

Step-by-step explanation:    

Given : Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same point. Alan races around the track in 45 seconds before Brian does and overtakes him every 9 minutes.

To find : What are their rates, in meters per minute?

Solution :

Let n represent the number of laps that Alan completes in 9 minutes.

Then n-1 is the number of laps Brian completes.

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\frac{9}{(n -1)}-\frac{9}{n} =\frac{3}{4}

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S=\frac{D}{T}

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Brian completes 3 laps in that 9-minute time, so his rate is

S_b=\frac{3\times 450}{9}

S_b=150 m/min

Therefore, Alan: 200 m/min

Brian: 150 m/min

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