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noname [10]
4 years ago
12

Which fraction is between 0 and 2/4

Mathematics
2 answers:
Gennadij [26K]4 years ago
7 0
2/4=1/2=0.5 _____ Between 0 and 0.5 are an infinity of fractions. Ex: 0.1 (=1/10), 0.2 (=2/10), 0.2356 (=2356/10000) etc.
AlladinOne [14]4 years ago
6 0
One of them is 1/4 i hope this will help

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if a gas has a volume of 1 L at a pressure of 270 kPa, what volume will it have when the pressure is increased to 540 kPa? Assum
lord [1]
The answer would be: 0.5L

This question can be solved using the ideal gas formula PV=nRT where
P= pressure
V= volume
n= number of molecule
R= constant
T= temperature


In this question, the temperature and number of the particle are not changed. The pressure is changed to twice amount. Since the pressure is inversely related to the volume, the volume should become half of the original.
PV=nRT 
V=nRT/P
V1/V2= (nRT/P1)/(nRT/P2)
V1/V2= (1/270)/(1/540)
V1/V2= (1/1)/(1/2)
V1/V2 = 2
V1= 2V2
1L= 2V2
V2= 1/2 L
8 0
3 years ago
I need help with this question please and thank you
inna [77]

d-13=5 is actually suppose to be solved liek this:

d - 13 = 5

   +13   +13

The absoulte value of 13 is 13, it is negative so you have to add 13 to get to 0 so it can be cancelled out.

5 0
3 years ago
Did I do this Math Right
kakasveta [241]
I cant answer if i dont know what math would you mind telling me what math

6 0
3 years ago
Parallel to y = 3x − 2 and passes through (1, 4)
4vir4ik [10]

Answer:

y=3x + 1

Step-by-step explanation:

slope is same

insert coordinates into x and y values

determine y-intercept

4 0
3 years ago
Help meh wit this bruh‍♂️
Leno4ka [110]

Answer:

a) m∠BPD = 120°

b) m∠BC + m∠AD = 120°

Step-by-step explanation:

a) To solve for question a, we make use of a theorem called the intersecting chord theorem. This states that:

The measure of the angle formed by two chords that intersect inside a circle is the average of the measures of the intercepted arcs.

The Interior angle =( The larger exterior arc + The smaller exterior arcs) ÷ 2

The larger exterior arc (m∠BD) = 170°

The small exterior arc (m∠CA) = 70°

m∠BPD = m∠BD + m∠CA/2

m∠BPD = 170° + 70°/2

= 240°/2

= 120°

b) We are to find m∠BC + m∠AD

The sum of exterior angles in a circle = 360°

360° = m∠BD + m∠CA + m∠BC + m∠AD

360° = 170° + 70° + m∠BC + m∠AD

360° = 240 + m∠BC + m∠AD

360 - 240° = m∠BC + m∠AD

Thererefore,

m∠BC + m∠AD = 120°

6 0
3 years ago
Read 2 more answers
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