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noname [10]
3 years ago
12

Which fraction is between 0 and 2/4

Mathematics
2 answers:
Gennadij [26K]3 years ago
7 0
2/4=1/2=0.5 _____ Between 0 and 0.5 are an infinity of fractions. Ex: 0.1 (=1/10), 0.2 (=2/10), 0.2356 (=2356/10000) etc.
AlladinOne [14]3 years ago
6 0
One of them is 1/4 i hope this will help

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Answer:

base =7.6 cm

Step-by-step explanation:

area of a triangle =base * height/2

=11.02*2 =base *height

22.04=base *2.9

22.04/2.9 =base

7.6 =base

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Find the slope of the line that passes through the points (1,-4) and (3,-1).
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3 years ago
How would i do this problem <br>slope= -2, y-intercept = 7
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SINCE the slope is -2 it would be like this -2/1 but first plot the y-intercept onto the graph and go down 2 and over 1.
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2 years ago
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Find the value of X, rounded to the nearest tenth. <br> A. 31.8<br> B. 31.4<br> C. 10.3<br> D. 10.7
Alenkinab [10]

Answer:

B. 31.4

Step-by-step explanation:

To find x, the hypotenuse, we need to use sin because we have been given the <u>opposite</u> (the side opposite the angle 35°) and we need to work out the <u>hypotenuse</u> (the longest or <em>slanted</em> side):

SOH, CAH, TOA

sin(θ) = opposite ÷ hypotenuse

Sub in the values (we don't know the hypotenuse so i've called it x):

sin(35) = 18 ÷ x (multiply both sides by x)

x × sin(35) = 18 (divide both sides by sin(35))

x = 18 ÷ sin(35) = 31.38204...

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Hope this helps!

7 0
2 years ago
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The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.​
erma4kov [3.2K]

Answer:

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm

\\

Step-by-step explanation:

Given:

  • Radius of the cylinder = 7 cm
  • Height of the cylinder = 10 cm

\\

To Find:

  • Curved surface area
  • Volume

\\

Solution:

\\

Using formula:

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA  \: of  \: cylinder = 2\pi rh}}}}}}  \:  \star \\  \\

<em>Substituting the required values: </em>

\\

\dashrightarrow \:  \:  \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times  10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 2 \times 22 \times 10 \\  \\ \\   \dashrightarrow \:  \:  \sf CSA {(cylinder)} = 44 \times 10 \\  \\  \\  \dashrightarrow \:  \:  \sf CSA {(cylinder)}  = 440 \:  {cm}^{2}  \\ \\ \\

Now,

\dashrightarrow \:  \:  { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}=  \pi {r}^{2} h}}}}}}  \:  \star \\  \\ \\

<em>Substituting the required values, </em>

\\

\dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \dfrac{22}{7}  \times  {(7)}^{2}  \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}=  \frac{22}{7}  \times 49  \times 10 \\ \\ \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\  \\  \dashrightarrow \:  \:   \sf Volume {(cylinder)}= 1540 {cm}^{3}  \\ \\ \\

Hence,

  • CSA of the cylinder = 440 sq. cm

  • Volume of the cylinder = 1540 cu. cm
8 0
2 years ago
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