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3 years ago

Can someone help me with this one i am confused

Mathematics

1 answer:

RideAnS [48]3 years ago

4 0

Answer:

Formula: (x^2 -h) +(y^2 -k)=r^2

The number on the right side of the = is the radius of the circle squared.

(h,k) is the center of the circle.

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a force of 2 pounds is needed to stretch a spring 8 inches.what force is required to stretch the spring 16 inches

Korvikt [17]

Answer:

Four (4) pounds

Step-by-step explanation:

Because we required two (2) pounds to stretch the spring eight (8) inches, we need double the force to stretch it sixteen (16) inches. Sixteen is just double the original amount, meaning we need four (4) pounds to stretch the spring sixteen inches.

Hope this helps!

5 0

3 years ago

Graph the line with slope – 2 passing through the point (-5,5).

34kurt

Answer:

y = -2x - 5

Step-by-step explanation:

y = -2x + b

- To find the y-intercept, plug the values of the variables.

5 = -2(-5) + b

5 = 10 + b

- Subtract 10 from both sides.

-5 = b

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3 years ago

A standard deck of 52 playing cards has 4 suits with 13 different cards in each suit. How many different five-card hands are pos

jok3333 [9.3K]

I think the answer is B

7 0

3 years ago

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PLEASE HELP (100 POINTS)

Artyom0805 [142]

$\\ \rm\Rrightarrow f(x)=-5cos\dfrac{x}{2}+5$

Compare to standard equation of SHM

$\\ \rm\Rrightarrow y=Acos(\omega x+\phi)$

Here

Amplitude=A=-5

$\\ \rm\Rrightarrow \omega x=\dfrac{x}{2}$

$\\ \rm\Rrightarrow \omega=1/2$

Well the above one are for extra knowledge .

Solution:-

$\\ \rm\Rrightarrow 10=-5cos\dfrac{x}{2}+5$

$\\ \rm\Rrightarrow 10-5=-5cos\dfrac{x}{2}$

$\\ \rm\Rrightarrow 5=-5cos\dfrac{x}{2}$

$\\ \rm\Rrightarrow cos\dfrac{x}{2}=-1$

$\\ \rm\Rrightarrow \dfrac{x}{2}=cos^{-1}(-1)$

$\\ \rm\Rrightarrow \dfrac{x}{2}=\pi$

$\\ \rm\Rrightarrow x=2\pi$

So.

$\\ \rm\Rrightarrow x=2\pi+2\pi n$

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barxatty [35]

Answer:

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Step-by-step explanation:

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