All categories

3 years ago

A windmill’s blades move from the blowing wind. The movement of the blades represents energy.

Physics

2 answers:

Sav [38]3 years ago

5 0

kinetic and radiant Explanation: the guy above me said so.

NikAS [45]3 years ago

4 0

Answer:

Kinetic energy

radiant energy

Explanation:

Wind energy is harness in the rotation of blades and its motion is referred to as kinetic energy.
But energy is due to the position of objects called potential energy and the air moves, its blade captures kinetic energy and converts it into mechanical energy. Therefore, the rotation of the blade represents the kinetic energy.
Radiant energy is transmitted only by waves or sometimes by particles. This is the energy emitted by electromagnetic radiation. It is also a kind of kinetic energy so this is because the particles move when light, heat and radiation are taken from one source to another.
Therefore, radiant energy is seen when visible light allows people to see where they are going

You might be interested in

while racing on a flat track, a car rounds a curve of 28m radius and instantaneously experiences a centripetal acceleration of 1

liubo4ka [24]

When a body strictly moves on a curve, it's velocity at a point is tangential to the curve at that point.

Centripetal acceleration is the acceleration that a body experiences by the virtue of change in it's tangential velocity. It is directed towards the centre and mathematically is v^2/R where v is the speed at the instant.

So, 18 = v^2/R
v^2 = 504
v = 6√14

4 0

4 years ago

One of the harmonics of a column of air in a tube that is open at one end and closed at the other has a frequency of 448 hz, and

Lelechka [254]

The general formula for the frequency of the nth-harmonic of the column of air in the tube is given by
$f_n = n f_1$
where f1 is the fundamental frequency.

In our problem, we have two harmonics, one of order n and the other one of order (n+1) (because it is the next higher harmonic), so their frequencies are
$f_n = n f_1$
$f_{n+1} = (n+1) f_1$
so their difference is
$f_{n+1} - f_n = (n+1) f_1 - n f_1 = (n+1-n) f_1 = f_1$

So, the difference between the frequencies of the two harmonics is just the fundamental frequency of the column of air in the tube, which is:
$f_1 = 576 Hz - 448 Hz = 128 Hz$

7 0

4 years ago

A billiard ball moving at 0.5 m/s strikes another identical billiard ball, which is at rest, in an elastic head-on collision on

NikAS [45]

Answer: assuming that the billiard balls are of identical weight the impacted billiard ball will move forward at around 0.5m/s (not considering energy conservation). The ball impacting the 2nd one would stop because most of its Kinetic energy would have been transferred into the not moving ball.

Explanation: hope this helps!

4 0

4 years ago

A spring-mounted chair in which the astronaut sits, can be used to find the mass of an astronaut. The chair is then made to osci

emmainna [20.7K]

Answer:

M = 175 kg

Explanation:

In the resolution of the harmonic oscillator movement of a system and a mass with a spring, the angular velocity is

w = √ k / m

Where k is the spring constant and m the mass

In this case the mass is the mass of the chair (m) plus the mass of the astronaut (M)

M all = m + M

The angular velocity and the period are related by

w = 2π / T

Substituting

2π / T = √(k/(m + M))

We calculate the astronaut's mass

4π² / T² = k / (m + M)

M = k T² / 4π² - m

M = 569 3.6² /(4π²) - 11

M = 186.8 - 11

M = 175 kg

4 0

4 years ago

ANSWER ASAP PLS!!!

kodGreya [7K]

Answer:

A solenoid field is increased with the increase in the current flow through the coil.

Explanation:

A solenoid is a current carrying coil with a significant number of loops. It works like an electromagnet inside which, a uniform and strong magnetic field is created. The magnetic field outside the solenoid field is nearly zero but not exactly zero.

While experimenting with the solenoid, scientists came to know that the magnetic field generated by the solenoid increases with the increase in the current, flowing through the solenoid.

The magnetic field works strongly around the arena of coil. The field changes its direction only near the ends and gets weak. Else its uniform throughout the loops.

The magnetic field inside the solenoid can be formulated as,

$B=\mu n I$

Where,

B = Magnetic field generated by the solenoid

$\mu$ = Constant

I = Current flowing through the loops of the solenoid

5 0

3 years ago