while racing on a flat track, a car rounds a curve of 28m radius and instantaneously experiences a centripetal acceleration of 1
1 answer:
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Answer:
B. The buoyant force on the copper block is greater than the buoyant force on the lead block.
Explanation:
Given;
mass of lead block, m₁ = 200 g = 0.2 kg
mass of copper block, m₂ = 200 g = 0.2 kg
density of water, ρ = 1 g/cm³
density of lead block, ρ₁ = 11.34 g/cm³
density of copper block, ρ₂ = 8.96 g/cm³
The buoyant force on each block is calculated as;
The buoyant force of lead block;
The buoyant force of copper block
Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block
Answer:
5 ohms
Explanation:
Given:
EMF of the ideal battery (E) = 60 V
Voltage across the terminals of the battery (V) = 40 V
Current across the terminals (I) = 4 A
Let the internal resistance be 'r'.
Now, we know that, the voltage drop in the battery is given as:
Therefore, the voltage across the terminals of the battery is given as:
Now, rewriting in terms of 'r', we get:
Plug in the given values and solve for 'r'. This gives,
Therefore, the internal resistance of the battery is 5 ohms.
Answer:
(a)
(b)
Explanation:
Given:
Point source
Distance from source Part a
Distance from source Part b
Solution:
Part (a)
Using intensity formula at distance L from an isotropic point.
-------------------(1)
Substitute and
in equation 1..
Part (b)
Substitute and
in equation 1.
Therefore, the intensity at distance 1.6 m from the source:
.
And, the intensity at distance 2.2 m from the source:
.