Is a reflection matter?

Physics

1 answer:

azamat2 years ago

7 0

Answer:

Yes, because everything bounce off in every surface around any object.

Explanation:

You might be interested in

A brave child decides to grab onto an already spinning merry‑go‑round. The child is initially at rest and has a mass of 25.5 kg.

Svetllana [295]

Answer:

72.75 kg m^2

Explanation:

initial angular velocity, ω = 35 rpm

final angular velocity, ω' = 19 rpm

mass of child, m = 15.5 kg

distance from the centre, d = 1.55 m

Let the moment of inertia of the merry go round is I.

Use the concept of conservation of angular momentum

I ω = I' ω'

where I' be the moment of inertia of merry go round and child

I x 35 = ( I + md^2) ω'

I x 35 = ( I + 25.5 x 1.55 x 1.55) x 19

35 I = 19 I + 1164

16 I = 1164

I = 72.75 kg m^2

Thus, the moment of inertia of the merry go round is 72.75 kg m^2.

5 0

2 years ago

Which type of transformer is found outside a residential house

KonstantinChe [14]

The type of transformer that is found outside a residential house is :
step-down transformer
In step-down transformer, the secondary voltage is less than the primary voltage, which will reduce the voltage from the primary win.

7 0

2 years ago

What is the displacement of the particle in the time interval 5 seconds to 8 seconds?

Dmitriy789 [7]

The displacement is the vector with

magnitude
   distance between position at 5 sec and position at 8 sec
and direction
   direction from position at 5 sec to position at 8 sec .

The route followed during the time interval is irrelevant.

3 0

2 years ago

Read 2 more answers

A sled is accelerating down a hill at a rate of 1 m s2 . If the mass of the sled is suddenly cut in half and the net force on th

mihalych1998 [28]

We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,
$a'= \frac{2F}{ \frac{m}{2} } = \frac{4F}{m} = 4\frac{F}{m}$
But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.

4 0

2 years ago

A .025 kg bullet is moving at 350 m/s when it hits and then passes through a 7 kg block of wood. After the bullet passes through

slamgirl [31]

Answer:

The final velocity of the wooden block is equal to $1.035 m/s$