Question

Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0? u2 – 11u + 24 = 0 where u = (x2 – 1) (u2)2 – 11(u2) + 24 where u = (x2 – 1) u2 + 1 – 11u + 24 = 0 where u = (x2 – 1) (u2 – 1)2 – 11(u2 – 1) + 24 where u = (x2 – 1)
please answer quickly timed test

Answer 1

we have

$(x^{2}-1)^{2}-11(x^{2}-1)+24=0$ --------> equation

Let

$u=x^{2}-1$

substitute the value of u in the equation

$(u)^{2}-11(u)+24=0$

$u^{2}-11u+24=0$

therefore

the answer is the first option

$u^{2}-11u+24=0$  where  $u=x^{2}-1$

Answer 2

u2 – 11u + 24 = 0 where u = (x2 – 1) the first awnser, a.