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PSYCHO15rus [73]
3 years ago
5

Factor 4x^2 -6w+2x-12xw

Mathematics
2 answers:
kirill [66]3 years ago
7 0

Answer:

2(2x+1)(x-3w)

Flauer [41]3 years ago
3 0
We could break this up into
(4x^2 - 6w) + (2x - 12xw)
The only thing the first term has in common is a 2. The second term has a 2 and an x in common. So:

2(2x^2 - 3w) + 2x(1 - 6w)
You might be interested in
Consider the sequence given by a plus 8 pattern: 2, 10, 18, 26, ….
Finger [1]

Answer:

n = 1 second formula

n = 0 first formula

Step-by-step explanation:

I answer this in the other question you put, here it is again.

This is easy to get. We know the sequence cause it follows a pattern of 8, so let's try some values of n from 1 to 4, to get those numbers with the first formula:

n = 1,2,3,4

f(1) = 8(1) + 2 = 10

f(2) = 8(2) + 2 = 18

f(3) = 8(3) + 2 = 26

f(4) = 8(4) + 2 = 34

As you can see, with the first formula, the first term is 10, and not 2. The only way to get 2 with n = 1 is with the second formula:

f(1) = 8(1) - 6 = 2

f(2) = 8(2) - 6 = 10

f(3) = 8(3) - 6 = 18

f(4) = 8(4) - 6 = 26

With n = 1, the second formula was better and correct.

The first formula could be right only beggining with n = 0. Here is the proof:

f(0) = 8(0) + 2 = 2

6 0
3 years ago
What is the value of x <br> (X+40) (3x) <br> A. 20<br> B. 35<br> C. 60<br> D. 70
shtirl [24]

Answer: A. 20 is the answer.

Step-by-step explanation:

x+40 = 3x

or, 40 = 3x-x

or, 2x = 40

or, x = 40/2

so, x = 20

4 0
3 years ago
Y is a random variable that is distributed N(-16, 1.21). Find k such that Prob(-15.043 &lt; Y ≤ k) = 0.1546. (Round your answer
IgorLugansk [536]

Transform <em>Y</em> to <em>Z</em>, which is distributed N(0, 1), using the formula

<em>Y</em> = <em>µ</em> + <em>σZ</em>

where <em>µ</em> = -16 and <em>σ</em> = 1.21.

Pr[-15.043 < <em>Y</em> ≤ <em>k</em>] = 0.1546

Pr[(-15.043 + 16)/1.21 < (<em>Y</em> + 16)/1.21 ≤ (<em>k</em> + 16)/1.21] = 0.1546

Pr[0.791 < <em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] - Pr[<em>Z</em> < 0.791] = 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] = 0.1546 + Pr[<em>Z</em> < 0.791]

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546 + 0.786

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.940

Take the inverse CDF of both sides (<em>Φ(x)</em> denotes the CDF itself):

(<em>k</em> + 16)/1.21 ≈ <em>Φ⁻¹</em> (0.940) ≈ 1.556

Solve for <em>k</em> :

<em>k</em> + 16 = 1.21 • 1.556

<em>k</em> ≈ -14.118

8 0
3 years ago
Determine if the expression - x^3 y^5 / 3 is a polynomial or not. If it is a polynomial, state the type and degree of the polyno
kykrilka [37]

Answer:

it is not a polynomial it has no degree either .. and we only classify polynomials in accordance with their degrees

4 0
2 years ago
Find the valuesof integers x and y: x^(8)+16y^(8)=0
avanturin [10]

Answer:

x=0,

y=0

Step-by-step explanation:

x^8+16y^8=0\\(x^{2}) ^{4} +16(y^{2}) ^{4} =0\\x^2\geq 0,y^2\geq 0\\sum~ of ~two ~positive~ integers ~is~ zero~ if~ each=0\\so~x=0,~y=0

8 0
3 years ago
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