The answer is c alternate exterior angles
Answer:
.00114771
<em>hope this helps, good luck :)</em>
Complete Question
Consider the isosceles triangle. left side (2z+8)units, bottom of triangle (4z-10)units, right side of triangle (2z+8) units Part A Which expression represents the perimeter of the triangle? a.(4z+16) units b.(6z−2)units c.(8z−16) units d.(8z+6) units
Answer:
d. (8z + 6) units
Step-by-step explanation:
The formula for the Perimeter of a Triangle is :Side A + Side B + Side C
Hence,
(2z + 8)units + (4z - 10) units + (2z + 8)units
= (2z + 8 + 4z - 10 + 2z + 8)units
Collect like terms
= 2z + 4z + 2z + 8 - 10 + 8
= 8z + 6 units
The expression that represents the perimeter of the triangle is (8z +6) units
The angle is arctan(3/4) => sin(2t) = sin(2arctan(3/4)) =
2sin(arctan(3/4))cos(arctan(3/4))
Let z = arctan(3/4) => tan(z) = 3/4
2sin(arctan(3/4))cos(arctan(3/4)) = 2sin(z)cos(z) = 2(3/5)(4/5) = 24/25
<span>cos(2t) = cos^2(t) - sin^2(t) = cos^2(z) - sin^2(z) = (4/5)^2 - (3/5)^2 = (16 - 9)/25
= 7/25
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