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qwelly [4]
3 years ago
13

If the vapor pressure of an aqueous solution containing 6.00 moles of a nonvolatile solute has a vapor pressure of 19.8 torr, an

d given that the vapor pressure of water at room temperature is 23.7 torr, how many total moles are present in solution? Your answer should have three significant figures.
Chemistry
1 answer:
Margaret [11]3 years ago
5 0

Answer:

36.5 mol

Explanation:

The vapor pressure of a solution of a non volatile solute in  water is given by Raoult´s law:

P H₂O = χ H₂O x P⁰ H₂O

where  χ H₂O  is the mole fraction of water in the solution and P⁰ H₂O

In the turn the mole fraction is given by

χ H₂O = mol H₂O / total # moles = mol H₂O /ntot

Thus

P H₂O = mole H₂O / n tot  x   P⁰ H₂0

now the mol of H₂O is equal n tot - 6  mol solute

Plugging the values given in the question and  solving the resultant equation

19.8 torr = ( ntot - 6 ) x 23.7 torr / n tot

19.8 ntot  = 23.7 ntot - 142.2

ntot = 36.5 ( rounded to 3 significant figures )

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