For the following equation to be bal

What is the concentration of a solution formed by mixing 89.94 grams of cobalt (II)

bezimeni [28]

Answer:

0.47 M

Explanation:

The concentration of the solution can be calculated using the following equation:

$C = \frac{\eta}{V} = \frac{m}{M*V}$

Where:

V: is the volume of the solution = 68.6x10⁻² L

η: is the moles of cobalt (II) sulfate

m: is the mass of cobalt (II) sulfate = 89.94 g

M: is the molar mass of cobalt (II) sulfate = 281.103 g/mol

The concentration of cobalt (II) sulfate is:

$C = \frac{m}{M*V} = \frac{89.94 g}{281.103 g/mol*68.6 \cdot 10^{-2} L} = 0.47 mol/L$

We used the molar mass of the cobalt (II) sulfate heptahydrate (281.103 g/mol) since it is one of the most common salts of cobalt.

Therefore, the concentration of a solution of cobalt (II) sulfate is 0.47 M (assuming that the cobalt (II) sulfate is heptahydrate).

I hope it helps you!

3 0

3 years ago

Read 2 more answers

Which of the following elements in group 1 of the periodic table has the smallest atomic radius?

ivann1987 [24]

The element in group 1 of the periodic table that had the smallest atomic radius is A. Lithium.

6 0

3 years ago

Which process is an oxidation?

Zarrin [17]

The problem has to do with oxidation states of the matter. The oxidation state of oxygen will always be -2 with the exception of peroxides which will have a state of -1. The overall balanced state of chemical compounds will be 0, so the oxidation state of Mn in MnO2 will be +4. The oxidation state of MnO4- will then be +7 to balance out to the negative one charge. The state change from +4 to +7 is 3, thus three electrons have to be lost in order for this to happen; a loss of a charge of -3 results in an increase of charge of 3. Oxidation is always the process of 'losing' electrons.

E] MnO2(s) MnO4-(aq

4 0

3 years ago

Complete and balance the following acid-base reaction equation ______HNO3 + ______ Mg(OH)2 ------>

jekas [21]

Answer

_2 HNO₃ + 1 Mg(OH)₂ → 1 Mg(NO₃)₂ + 2 H₂O

Explanation

Given:

______HNO3 + Mg(OH)2 ------>

Solution:

Note that the reaction between an acid and a base will give salt and water only.

Hence the complete reaction of the given equation is:

___HNO₃ + Mg(OH)₂ → Mg(NO₃)₂ + H₂O

To get the balanced equation for the acid-base reaction, 2 moles of HNO₃ will react with 1 mole of Mg(OH)₂ to produced 1 mole of Mg(NO₃)₂ and 2 moles of H₂O.

Therefore, the complete and balanced equation for the given acid-base reaction is:

_2 HNO₃ + 1 Mg(OH)₂ → 1 Mg(NO₃)₂ + 2 H₂O

5 0

1 year ago

What is the daughter nucleus (nuclide) produced when 64 Cu Cu64 undergoes beta decay by emitting an electron? Replace each quest

kenny6666 [7]

Answer: The daughter nuclide formed by the beta decay of given isotope is $_{30}^{64}\textrm{Zn}$

Explanation:

Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.

The released beta particle is also known as electron.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

We are given:

Parent isotope = $_{29}^{64}\textrm{Cu}$

The chemical equation for the beta decay process of $_{29}^{64}\textrm{Cu}$ follows:

$_{29}^{64}\textrm{Cu}\rightarrow _{30}^{64}\textrm{Zn}+_{-1}^0\beta$

Hence, the daughter nuclide formed by the beta decay of given isotope is $_{30}^{64}\textrm{Zn}$

4 0

3 years ago