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Roman55 [17]
3 years ago
9

3. 2.15 x 3.1 x 100 =

Chemistry
2 answers:
jasenka [17]3 years ago
7 0
The answer would be 666.5 :)
jeka943 years ago
3 0

Answer:

666.5

Explanation:

Multiply 2.15 and 3.1 to get 6.665.

6.665×100≈666.5

Multiply 6.665 and 100 to get 666.5.

666.5

You might be interested in
Which characteristic of the elements increases as you move across a period from left to right?
topjm [15]

Answer:

Valence electrons

Explanation:

In a period, the number of valence electrons increases (mostly for light metal/elements) as we move from left to right side

6 0
2 years ago
The volume of a sample of gas is 0.5 L and the pressure is 0.98 atm. The volume is increased to 1.0 L. Show the set
meriva

Given,

P1 = 0.98 atm

V1 = 0.5 L

V2 = 1.0 L

P2 = ?

Solution,

According to Boyle's Law,

P1V1 = P2V2

0.98 × 0.5 = 1.0 × P2

P2 = 0.98 × 0.5 × 1.0

P2 = 0.49 atm

Answer - The new pressure is 0.49 atm.

5 0
3 years ago
I need helpppp plzzzz
Inessa [10]

Answer:

at first i would like to tell which class

Explanation:

125000 is the answwr

8 0
3 years ago
What is the <br> formula for gunpowder
mrs_skeptik [129]

Here is the chemical equation for gun powder, in it’s simple form:

<span>2 KNO3 + S + 3 C → K2S + N2 + 3 CO2.</span>

This is the same simplified formula, only balanced:

<span>10 KNO3 + 3 S + 8 C → 2 K2CO3 + 3 K2SO4 + 6 CO2 + 5 N2.</span>

3 0
3 years ago
Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr
Delvig [45]
<h2>Hello!</h2>

The answer is: Charle's Law.

<h2>Why?</h2>

The law that states that the volume and absolute temperature of a fixed quantity of gas (ideal gas) are proportional under constant pressure is the Charle's Law, also known as the law of volumes.

The law describes how a gas kept under constant pressure tends to expand when the temperature increases and it's described by the following equation:

\frac{V}{T}=k

Where,

V=Volume\\T=Temperature\\k=constant

Also, to describe the relationship between two differents volumes at different temperatures, we have:

\frac{V_{i}}{T_{i}}=\frac{V_{f}}{T_{f}}

Where,

V_{i}=InitialVolume\\T_{i}=InitialTemperature\\V_{f}=FinalVolume\\T_{f}=FinalTemperature

Have a nice day!

8 0
3 years ago
Read 2 more answers
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