Answer:
x ≤ 6 and x ≥ 2
Step-by-step explanation:
For now, we will start with doing each problem at a time. Here is your equation:
2x - 4 ≤ 8
First, you want to get the variable by itself. So, you add 4 to both sides. It will look like this:
2x - 4 ≤ 8
+ 4 + 4
The four being added on the left side cancels out, and you add 4 to 8. Now, it should look like this:
2x ≤ 12
Next, you want the x by itself. So, you would divide both sides by 2.
2x ≤ 12
/2 /2
2 divided by 2 cancels out, and 12 divided by 2 equals 6. Now, you have a final answer of:
x ≤ 6
But, you now have to do the other one!
Here is what you start off with:
x + 5 ≥ 7
First, you want the variable side by itself. So, you subtract 5 from both sides.
x + 5 ≥ 7
- 5 -5
Now, you have this:
x ≥ 2
Because the variable is already by itself, you don't need to do any more division and this is you final answer. Now put both answers you got together which equals:
x ≤ 6 and x ≥ 2
So you would do 5*2x +5*-8 +15=-15
Then simplify so it would be 10x + -40 + 15 = -15
Then add -40 and 15 together
Then it would be 10x + -25 = -15
Then add 25 to -25 and -15
So it would be 10x = 10
And then divide 10 from 10 with would be 1 so x = 1
Answer:
your answer is 8/6
Step-by-step explanation:
the equation for tangent is opposite side/adjacent side but you cant use the hypotenuse which is 10 so you end up with the opposite side 8 and the adjacent side 6 so the final answer comes to 8/6
Use quadratic formula
if you had ax^2+bx+c=0, then
x=
a=1
b=?
c=34
subsitute
=5+/-3i
=5+/-3i
make 5+/-3 into fraction over 2,(10+/-6i)/2
=(10+/-6i)/2
multiply both sides by 2
=10+/-6i
we conclude that -b=10
b=-10
ok so equaton is
x^2-10x+34
Maybe a square that is 4 on every side
