Answer:
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Step-by-step explanation:
Answer:
a. 5 + x = -5 (Subtraction) 0.
b. -17 + x = 0 (Addition) 17.
c. 30 + x = 0 (Subtraction) -30.
d. x + (-27) = 0 (Addition) 27.
e. x + (-30) = 0 (Addition) 30.
Step-by-step explanation:
In this exercise, students are required to match each equation with its solution. (The corresponding operations must be presented at the end of this point
a. 5 + x = -5 (Subtraction) 0.
x = -5 - 5
x = 0
b. -17 + x = 0 (Addition) 17.
x = 0 + 17
x = 17
c. 30 + x = 0 (Subtraction) -30.
x = 0 - 30
x = -30
d. x + (-27) = 0 (Addition) 27.
x - 27 = 0
x = 0 + 27
x = 27
e. x + (-30) = 0 (Addition) 30.
x - 30 = 0
x = 0 + 30
x = 30
Answer:Should be 200 ft, 100 ft, 200 ft, and 100 ft
Step-by-step explanation:
Answer:
Answer:
t ≅ 5.09 min
Step-by-step explanation:
we have that if in 4000 L/sol there is 132 kg salt and the pumping speed is 12L/s, we must find how much of salt is pumping per second and then find the amount of salt remaining
12L/s*132kg salt/4000L = 0.396 Kg salt/s, this means that 0.396 kg per second comes out , It should be found that the amount of salt must be drained so that only 11 kg of salt remain
132kg salt - 11 kg salt = 121 kg salt, so
121Kg salt*s/0.396Kg salt ≅ 305.55 s ⇒ 305.55s*min/60s ≅ 5.09 min
Step-by-step explanation:
Ok so it would be 3/4 times 20
And you would get 15
I would draw a circle that adds up to 100
To do this multiply the 20 five times to get 100
Then multiply the 15 by the same number (5) to get 75
Draw a circle and shade in 75% of it and that is your answer
