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Kay [80]
2 years ago
13

Suppose there are 1,000 total sales representatives in the midwest and northeast regions, with 500 sales re

Mathematics
1 answer:
Maru [420]2 years ago
4 0

Making 20 groups of 10 is the sampling strategy that can be used to select 200 sales representatives.

What is sampling?

Sampling is the phrase used to describe a statistical procedure in which a predetermined number of observations are chosen from a larger population. More precisely, sampling can be described as the process of choosing a portion of a statistical population in order to estimate the characteristics of the entire population. Samples that are representative of the population under study are sought for by statisticians.

Making 20 groups of 10 is the most effective way of sampling that can be employed here for the sales director to incorporate 200 sales representatives in this situation, with an equal amount of representatives from each region.

Learn more about sampling here:

brainly.com/question/11045407

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What is the answer and how do you find it? Show work or no points.
NNADVOKAT [17]

Answer:

Answer is D

Step-by-step explanation:

I kinda understand it but it need to be neat so yh next time you have aa problem like this just write it neat for people to understand cleary what is your question.

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3 years ago
Help<br><br> find the value of x
Masteriza [31]

Answer: i believe

that x does not have a value

Step-by-step explanation:"variable" or sometimes an "unknown"

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2 years ago
Solve -1 7/8 * (-2 2/5)
Semmy [17]

Answer:

exact form:

9/2

decimal form:

4.5

mixed number form:

4 1/2

Step-by-step explanation: sorry if this wasnt what you were looking for.

3 0
3 years ago
Factor completely. <br> <img src="https://tex.z-dn.net/?f=x%5E%7B8%7D-%5Cfrac%7B1%7D%7B81%7D" id="TexFormula1" title="x^{8}-\fra
Eduardwww [97]

We have 3⁴ = 81, so we can factorize this as a difference of squares twice:

x^8 - \dfrac1{81} = \left(x^2\right)^4 - \left(\dfrac13\right)^4 \\\\ x^8 - \dfrac1{81} = \left(\left(x^2\right)^2 - \left(\dfrac13\right)^2\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(\left(x^2\right)^2 + \left(\dfrac13\right)^2\right) \\\\ x^8 - \dfrac1{81} = \left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)

Depending on the precise definition of "completely" in this context, you can go a bit further and factorize x^2-\frac13 as yet another difference of squares:

x^2 - \dfrac13 = x^2 - \left(\dfrac1{\sqrt3}\right)^2 = \left(x-\dfrac1{\sqrt3}\right)\left(x+\dfrac1{\sqrt3}\right)

And if you're working over the field of complex numbers, you can go even further. For instance,

x^4 + \dfrac19 = \left(x^2\right)^2 - \left(i\dfrac13\right)^2 = \left(x^2 - i\dfrac13\right) \left(x^2 + i\dfrac13\right)

But I think you'd be fine stopping at the first result,

x^8 - \dfrac1{81} = \boxed{\left(x^2 - \dfrac13\right) \left(x^2 + \dfrac13\right) \left(x^4 + \dfrac19\right)}

6 0
3 years ago
DETERMINE IF A FUNCTION OR NOT<br><br>WILL MARK BRAINLIEST FOR CORRECT ANSWERS
balu736 [363]

Answer:

Relation 3: yes, it can be a function

Relation 4: no, it cannot be a function

Step-by-step explanation:

in a function, for every input x there can only be one correlating output y.

4 0
3 years ago
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