<span>1.) d - 1 > -3 and d + 2 < 5
d-1>-3→d-1+1>-3+1→d>-2
</span>d+2<5→d+2-2<5-2→d<3
<span>Part 1: The solution is d>-2 and d<3.
Part 2: There would be an open circle on -2 and an open circle on 3.
Part 3: The shading is between the two numbers.
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2.) -3k + 7 > -5 and -7k + 5 < -2
-3k+7>-5→-3k+7-7>-5-7→-3k>-12→(-1/3)(-3k>-12)→k<4
-7k+5<-2→-7k+5-5<-2-5→-7k<-7→(-1/7)(-7k<-7)→k>1
</span>Part 1: The solution is k>1 and k<4.
Part 2: There would be an open circle on 1 and an open circle on 4.
Part 3: The shading is between the two numbers.<span>
3.)-5 < 2y - 3 < 23 (Hint: refer to example 2 in the lesson)
-5<2y-3<23→-5+3<2y-3+3<23+3→-2<2y<26→-2/2<2y/2<26/2→-1<y<13
</span>Part 1: The solution is y>-1 and y<13.
Part 2: There would be an open circle on -1 and an open circle on 13.
Part 3: The shading is between the two numbers.<span>
4.)x - 4 < 5 or x + 2 > 15
x-4<5→x-4+4<5+4→x<9
x+2>15→x+2-2>15-2→x>13
</span>Part 1: The solution is x>9 or x>13.
Part 2: There would be an open circle on 9 and an open circle on 13.
Part 3: The shading is from 9 to the left and from 13 to the right.<span>
5.) 5x - 4 > 6 or -4x + 5 > 1
5x-4>6→5x-4+4>6+4→5x>10→5x/5>10/5→x>2
-4x+5>1→-4x+5-5>1-5→-4x>-4→(-1/4)(-4x>-4)→x<1
</span>Part 1: The solution is x<1 or x>2.
Part 2: There would be an open circle on 1 and an open circle on 2.
Part 3: The shading is from 1 to the left and from 2 to the right.
Answer:
(D) Pie chart
Step-by-step explanation:
The most appropriate method to represent the resulting data is the pie chart. This is because, in this sample, the variables are few and of nominal type.
Of the rest of the options, the only other that could be used is the histogram, since it can represent nominal variables with their corresponding frequency. The rest of the options have other uses not appropriate for this type of sample.
The answer is:
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[C]: <span>First, prove that ∠ABE is congruent to ∠CBD because vertical angles are congruent. Then use SSA to prove the triangles are congruent.
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All you have to do is plug in the 2 for x which gives you 8 as the answer
0.30 is the same as 3/10 so then you would add 3/10 and 4/10 which equals 7/10 which then gives you with 3/10 ice cream left