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4 years ago

16 plus 5 times a number is more than the number minus 8. Write an inequality and solve it

Mathematics

1 answer:

Radda [10]4 years ago

8 0

n > -6 is the inequality for 16 plus 5 times a number is more than the number minus 8

Solution:

Given statement is:

16 plus 5 times a number is more than the number minus 8

We have to write a inequality

From given statement,

16 plus 5 times a number is more than the number minus 8

Let the number be "n"

Therefore,

16 plus 5 times "n" is more than "n" minus 8

Here, "plus" means addition and "minus" means subtraction and "times" means multiplication

Thus the statement is translated into inequality as:

$16 + 5n >n-8$

Simplify the inequality

$16 + 5n >n-8\\\\\mathrm{Subtract\:}16\mathrm{\:from\:both\:sides}\\\\16 + 5n -16 > n - 8 -16\\\\5n >n-24\\\\\mathrm{Subtract\:}n\mathrm{\:from\:both\:sides}\\\\5n-n>n-24-n\\\\\mathrm{Simplify}\\\\4n>-24\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\\\frac{4n}{4}>\frac{-24}{4}\\\\n>-6$

Thus the soultion is n > -6

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Brandon is cutting 9 boards for a woodworking project. Each board is 4 5/8 feet long. What is the total length of the boards

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41.625 feet long because it is the product of 4 5/8*9

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3 years ago

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Whats the vertex at of y-13=2(x+4)^2

Kipish [7]

The vertex form:
$y=a(x-h)^2+k$
(h,k) - the coordinates of the vertex

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3 years ago

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The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

NEED HELP ASAP!!!

patriot [66]

1.-7/4
2.1/7
3.-5/3
4.1/2
5.neither a parallelogram nor a trapezoid
6.neither pair of opposite sides is parallel

hope this help any one who need the answer

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4 years ago

The maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. A truck measures 162 inches in height.

Nutka1998 [239]

It would not pass under the bridge because ig you divide 162 by 12 it would equal 13.5

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4 years ago