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madreJ [45]
3 years ago
7

16 plus 5 times a number is more than the number minus 8. Write an inequality and solve it

Mathematics
1 answer:
Radda [10]3 years ago
8 0

n > -6 is the inequality for 16 plus 5 times a number is more than the number minus 8

<em><u>Solution:</u></em>

Given statement is:

16 plus 5 times a number is more than the number minus 8

We have to write a inequality

From given statement,

16 plus 5 times a number is more than the number minus 8

Let the number be "n"

Therefore,

16 plus 5 times "n" is more than "n" minus 8

Here, "plus" means addition and "minus" means subtraction and "times" means multiplication

Thus the statement is translated into inequality as:

16 + 5n >n-8

Simplify the inequality

16 + 5n >n-8\\\\\mathrm{Subtract\:}16\mathrm{\:from\:both\:sides}\\\\16 + 5n -16 > n - 8 -16\\\\5n >n-24\\\\\mathrm{Subtract\:}n\mathrm{\:from\:both\:sides}\\\\5n-n>n-24-n\\\\\mathrm{Simplify}\\\\4n>-24\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\\\frac{4n}{4}>\frac{-24}{4}\\\\n>-6

Thus the soultion is n > -6

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Find the quation of the quadratic function with roots 0 and 4 and a vertex at (2,-2)
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Answer:

y = (1/2)x² -2x

Step-by-step explanation:

recall that the general equation of a quadratic function is:

y = Ax² + Bx + C

given that 0 and 4 are roots, that means when x = 0 and x = 4, then  y = 0

From this we can get 2 points on the curve, namely,  (0,0) and (4,0)

substituting these points one at a time into the equation above,

for the first point (0,0),

0 = A (0)² + b(0) + C

C = 0

hence the equation becomes:    y = Ax² + Bx

for the 2nd known point (4,0)

0 = A(4)² + B(4)

0 = 16A + 4B   (divide both sides by 4)

0 = 4A + B

B = -4A    ------------(eq 1)

we are given a 3rd point, vertex at (2,-2)

for (2,-2)

-2 = A(2²) + B(2)

-2 = 4A + 2B   (divide both sides by 2)

-1 = 2A + B   (subtract 2A from both sides)

B = -1 -2A --------(eq 2)

solving the system of equations using the method of your choice in eq1 and eq 2 gives:

A = 1/2 and B = -2

hence the equation is

y = (1/2)x² -2x

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Which expression is equivalent to 3(2x−4)+4x−2
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In kite ABCD, mZBAE = 28º and mZBCE = 58°. Find mZABE.<br> B<br> E<br> А<br> С<br> D<br> mLABE =
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Answer:

m∠ABE = 62°

Step-by-step explanation:

Since, the given quadrilateral is a kite, diagonals will intersect at 90°.

Therefore, m∠AEB = m∠CEB = 90°

m∠BAE = 28° [Given]

m∠BCE = 58° [Given]

From ΔABE,

m∠BAE + m∠BEA + m∠ABE = 180°

28° + 90° + m∠ABE = 180°

m∠ABE = 180° - 118°

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