The sign of f on the interval -7/3 < x < -3/5 is always positive.
<h3>How to solve for the sign on the interval</h3>
We have the equation
(5x+3)(x−2)(3x+7)(x+5) > 0
Now when f(x) > 0
Then -7/3 < x < -3/5
This would tell us that the sign would become positive when it changes from the less than to greater than sign
<h3>Complete Question</h3>
f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2
What is the sign of f on the interval -7/3<x<-3/5?
answer choices
f is always positive on the interval
f is always negative on the interval
f is sometimes positive and sometimes negative on the interval
f is never positive or negative on the interval
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Answer:
-3
Step-by-step explanation
If s(t) is equal to -9 - 3t, its derivative is equal to -3 for all values of t. The instantaneous velocity is simply the derivative at that point, so it is -3.
Answer:
y=-4x-3
Step-by-step explanation:
y=mx+b
y=b=-3 ( y intercept is when x=0, then y=b=-3)
y=-4x-3
Exact form: X = -4/3, 2
Decimal form: x= -1.3 repeat, 2
Answer:
x=8,9
Step-by-step explanation:
x^2-17x+72=0
(x-8)(x-9)=0
x=8,9