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Jlenok [28]
3 years ago
14

Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. tan^2 B = 4

Mathematics
1 answer:
Anettt [7]3 years ago
7 0

<u>ANSWER</u>

B=63\degree


<u>EXPLANATION</u>

We want to solve the trigonometric equation;


tan^2(B)=4, where 0\degree \le B \le 90\degree.


Taking square root of both sides gives,


tan(B)=\pm \sqrt{4}


tan(B)=\pm 2


Since B is in the first quadrant, we proceed with;


tan(B)=2, because the tangent ratio is positive in the first quadrant.


\Rightarrow B =arctan(2)


\Rightarrow B =63.43\degree.


Correct to the nearest degree,


B =63\degree




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