Question

Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. tan^2 B = 4

Answer 1

ANSWER

$B=63\degree$

EXPLANATION

We want to solve the trigonometric equation;

$tan^2(B)=4$, where $0\degree \le B \le 90\degree$.

Taking square root of both sides gives,

$tan(B)=\pm \sqrt{4}$

$tan(B)=\pm 2$

Since B is in the first quadrant, we proceed with;

$tan(B)=2$, because the tangent ratio is positive in the first quadrant.

$\Rightarrow B =arctan(2)$

$\Rightarrow B =63.43\degree$.

Correct to the nearest degree,

$B =63\degree$