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AlladinOne [14]
3 years ago
13

BRAINLIEST! what are the next 2 terms in the geometric sequence? a1=2,r=-3

Mathematics
1 answer:
LenKa [72]3 years ago
8 0

Answer:

The next two terms after a1 is

-6 and then 18

Step-by-step explanation:

Geometric sequence means your pattern for the terms is multiplication by the same number.

So a1 is the first term and r is your common ratio.

The common ratio is what you are multiplying by each time to figure out the next term.

So the geometric sequence goes like this:

a1 ,  a1*r , (a1*r)*r or a1*r^2 , a1*r^3 ,....

So anyways you have

first term a1=2

second term a2=2(-3)=-6

third term a3=-6(-3)=18

And so on...

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-3y+1/3=-5/6y-5/2 what does y equal
kotykmax [81]

Answer:

17/13

Step-by-step explanation:

- 3y +  \frac{1}{3}  =  -  \frac{5}{6}y -  \frac{5}{2}  \\  -  \frac{18}{6}y  +  \frac{2}{6}  =  -  \frac{5}{6} y -  \frac{15}{6}  \\   \frac{2}{6}  +  \frac{15}{6}  =  -  \frac{5}{6} y +  \frac{18}{6} y \\  \frac{17}{6}  =  \frac{13}{6} y \\  \frac{6}{13}  \times  \frac{17}{6}  = y \\  \frac{17}{13}  = y

8 0
3 years ago
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garik1379 [7]

Answer:

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Step-by-step explanation:

Metronome gives a steady beat to people that cant count beats in a measure

8 0
3 years ago
The two figures shown are congruent. which statement is true?
Masteriza [31]

Answer:

1st Option

Step-by-step explanation:

Hope it helps

4 0
3 years ago
Read 2 more answers
Mario made this model to find the 3 digit number and a 1 digit number what multiplication sentence represents marios model
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3 years ago
In tossing four fair dice, what is the probability of tossing, at most, one 3
11Alexandr11 [23.1K]

<u>Answer- </u>

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

<u>Solution-</u>

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

P(A) =The \ probability \ of \ getting \ zero \ 3 =(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})=\frac{625}{1296} =0.48                    ( ∵ xxxx )

P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)(\frac{1}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6}) = 0.38                    ( ∵ 3xxx, x3xx, xx3x, xxx3 )

P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86

7 0
3 years ago
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