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3 years ago

What is 900x450-9???????????????????

Mathematics

2 answers:

Zolol [24]3 years ago

6 0

Answer:404991 is the anser hope this helps

bearhunter [10]3 years ago

3 0

404,991
PEMDAS
Multiplication comes before subtraction
900x450=405,000
405,000-9=404,991

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Suppose that you and a friend are playing cards and decide to make a bet. If your friend draws three non-face cards, where a fac

Darina [25.2K]

First let us calculate the probability that three non-face cards will be drawn in succession without replacement.

There are 40 non-face cards in a deck of 52 cards.

Probability of 3 successive non-face cards = (40/52)*(39/51)*(38/50) = 0.447

Therefore, the probability that it will not be 3 successive non-face cards is 1-0.447 = 0.553

Hence, for each game the expected return would be:

Return = 0.447 * (-$10) + 0.553 ($20) = $6.59 per bet

For 25 bets:

Total return = $6.59 * 25

Total return = $164.75

If the bet is performed 25 times, expect to win $164.75.

5 0

3 years ago

Which of the following is true regarding the solutions to the logarithmic equation below? 2 log Subscript 6 Baseline (x) = 2. lo

Serggg [28]

Option c: x=6 is a true solution and x=-6 is an extraneous solution.

Explanation:

The equation is $2 \log _{6} x=2$

Dividing both sides of the equation by 2, we get,

$\frac{2 \log _{6}(x)}{2}=\frac{2}{2}$

Simplifying,

$\log _{6}(x)=1$

Since, we know by the logarithmic definition, if $\log _{a}(b)=c$ , then $b=a^{c}$

Using this definition, we have,

$x=6^{1}$

Hence, $x=6$

Now, let us verify if $x=6$ is the solution.

Substitute $x=6$ in the equation $2 \log _{6} x=2$ to see whether both sides of the equation are true.

We have,

$2 \log _{6}(6)$

Using the log rule, $\log _{a}(a)=1$

We have,

$2*1=2$

Hence, both sides of the equation are equal.

Thus, $x=6$ is the true solution.

4 0

3 years ago

Read 2 more answers

The points on the graph show how much Chef Allen pays for different amounts of beans

Leni [432]

Answer:

See explanation

Step-by-step explanation:

The ordered pair (25,20) shows that Chef Allen pays $20 for 20 pounds of beans. The ratio of pounds to dollars is

$\dfrac{25}{20}=\dfrac{5}{4}$

A. Another plotted points are (5,4), (10,8), (15,12) and (20,16). Find the ratio of pounds to dollars in each case:

$(5,4):\ \ \ \dfrac{5}{4}\\ \\(10,8):\ \ \ \dfrac{10}{8}=\dfrac{5}{4}\\ \\(15,12):\ \ \ \dfrac{15}{12}=\dfrac{5}{4}\\ \\(20,16):\ \ \ \dfrac{20}{16}=\dfrac{5}{4}$

All points show the same ratio.

B. The line connecting given points is the graph showing how much Chef Allen pays for different amounts of beans. This line starts at the origin (0,0) and passes through the points (5,4), (10,8), (15,12) and (20,16).

C. If he cost of 25 pounds of beans is $20, then the cost of 50 pounds of beans is $40.

7 0

3 years ago

Read 2 more answers

A sample of 50 drills had a mean lifetime of 12.17 holes drilled when drilling a low-carbon steel. Assume the population standar

zmey [24]

Using the z-distribution, it is found that the 95% confidence interval for the mean lifetime of this type of drill, in holes drilled, is (10.4, 13.94).

We are given the standard deviation for the population, hence, the z-distribution is used. The parameters for the interval is:

Sample mean of $\overline{x} = 12.17$
Population standard deviation of $\sigma = 6.37$
Sample size of $n = 50$ .

The margin of error is:

$M = z\frac{\sigma}{\sqrt{n}}$

In which z is the critical value.

We have to find the critical value, which is z with a p-value of $\frac{1 + \alpha}{2}$ , in which $\alpha$ is the confidence level.

In this problem, $\alpha = 0.95$ , thus, z with a p-value of $\frac{1 + 0.95}{2} = 0.975$ , which means that it is z = 1.96.

Then:

$M = 1.96\frac{6.37}{\sqrt{50}} = 1.77$

The confidence interval is the sample mean plus/minutes the margin of error, hence:

$\overline{x} - M = 12.17 - 1.77 = 10.4$

$\overline{x} + M = 12.17 + 1.77 = 13.94$

The 95% confidence interval for the mean lifetime of this type of drill, in holes drilled, is (10.4, 13.94).

A similar problem is given at brainly.com/question/22596713

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3 years ago

You borrow 125,000 for 25 years at an APR of 6.5%. What will be your monthly payment?

Morgarella [4.7K]

$\bf \qquad \qquad \textit{Amortized Loan Value}
\\\\
pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right]
\\\\\\\\
\qquad 
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount}\\
\end{array}\to &
\begin{array}{llll}
125000
\end{array}\\
pymt=\textit{periodic payments}\\
r=rate\to 6.5\%\to \frac{6.5}{100}\to &0.065\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{APR, meaning once}
\end{array}\to &1\\

t=years\to &25
\end{cases}$

8 0

3 years ago