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UkoKoshka [18]
4 years ago
12

2/7 + 3/a = please help me

Mathematics
1 answer:
KATRIN_1 [288]4 years ago
4 0
2/7 = -3/a, (2/7)a = -3, a = -3/(2/7), so the answer would be -10.5 or -21/2
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Find the equation of the line that passes through the point left (-9,12) and is perpendicular to the line y=3/2x-1/2. Write the
ohaa [14]

Answer:

The answer to your question is: y = -2/3 x + 18

Step-by-step explanation:

Data

Point = (-9, 12)

line   y = 3/2x -1/2     perpendicular

Process

The line must be perpendicular to the line given. Then,

slope is the line given = 3/2, we change it because the lines must be perpendicular ,

New slope         M =  -2/3

New line       y-y1 = m(x - x1)

                     y - 12 = -2/3 (x + 9)             Substitution

                   3( y - 12) = -2(x + 9)

                   3y - 36 = -2x - 18                 Simplify

                   3y = -2x - 18 + 36

                   3y = -2x + 18

                      y = -2/3 x+ 18                      Result

8 0
3 years ago
Please help me, I’ll mark you ask brainliest:-) !!
antoniya [11.8K]

Answer:

enter t= 12

Step-by-step explanation:

I think it helps

4 0
3 years ago
Read 2 more answers
I think its the second one but I'm not sure..
yuradex [85]
Yes it’s correct. You just need to plug each of the x and y values to see if they satisfy the equation.
7 0
3 years ago
Please help will give brainliest
Firdavs [7]

Answer:

PLEASE GIVE BRAINLIEST IT IS 118

Step-by-step explanation:

(18x+28)+(7x+27) equals 180 degrees

25x+55= 180

25x=125

x=5

THIS MEANS THAT ANGLE ABC IS

18(5)+28.

90+28.

118 degrees. And since angle abc is equal to efg that is your answer.

6 0
3 years ago
Read 2 more answers
I'm awful at word problems someone please help
Lubov Fominskaja [6]

Your answer is B.

Flat fee is $250, so we cannot change this number.
585 - 250 = 335
335 (remaining cash) divided by 8 (price per student) = 41.875
Since we can't bring .8 of one student on the trip, we will round the number down to 41, because if we round up we will go over the budget of $585.

The maximum number of students a school can send is 41.
6 0
3 years ago
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