What’s the question please? I’d like to answer but I’m a bit confused
Answer:
1. Binding of insulin to the alpha subunit of the insulin receptor
2. Activation of insulin receptor tyrosine kinase
3. Phosphorylation of IRS proteins
4. Activation of PIP3-dependent protein kinase B (PDK1)
5. Phosphorylation of phosphinositide 3-kinase (PI-3K)
6. Conversion of PIP2 to PIP3
7. Activation of Akt
8. Glut4 receptors transported to cell membrane
mRNA would be CCAUCCUUUGGG
tRNA would be GGUAGGAAACCC
Answer:
Glaciers will only form under certain conditions and in specific environments. A cold climate and sufficient moisture in the air for the precipitation of snow are both necessary factors that permit at least some snow to last year-round. This allows for the build-up and compaction of snow that will eventually become glacial ice. Sufficiently cold climate conditions exist at high altitudes and high latitudes.
Explanation:
There must be landmasses at high latitudes for continental glaciers to occur, as they cannot form over open water. While persistent sea ice can and does form, because it floats, it does not flow as a glacier does.
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
