A: 1.5
c: 10/3, 3 1/3, 3.3 repeating
b: 20/3, 6 2/3, 6.6 repeating
c: 8/15
d: 1
the 1st, 2nd, and 3rd are correct
Answer:
PΔJKL=66
Step-by-step explanation:
so we are given the line segments JK, KL, and LJ which are tangent to k(O), and also that JA=9, AL=10, and CK=14
JL=JA+AL (parts whole postulate)
JL=9+10=19 (substitution, algebra)
JA=JB=9 (tangent segments from the same point are congruent)
CK=KB=14 (tangent segments from the same point are congruent)
JK=JB+KB (parts whole postulate)
JK=9+14=23 (substitution, algebra)
LA=LC=10 (tangent segments from the same point are congruent)
LK=LC+CK (parts whole postulate)
LK=10+14=24 (substitution, algebra)
Perimeter of ΔJKL=LK+KL+LJ (perimeter formula for triangles)
Perimeter of ΔJKL=23+24+19=66 (substitution, algebra)
The factored expression of the polynomial expression given as: x^2 - 3x - 18 is (x + 3)(x - 6)
<h3>How to match the
polynomial?</h3>
The polynomial expression is given as:
x^2 - 3x - 18
Express -3x as 3x - 6x
So, we have:
x^2 + 3x - 6x - 18
Factorize the polynomial expression
x(x + 3) - 6(x + 3)
Factor out x + 3
(x + 3)(x - 6)
Hence, the factored expression of the polynomial expression given as: x^2 - 3x - 18 is (x + 3)(x - 6)
Read more about expressions at:
brainly.com/question/723406
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