Write an expression for the sequence of operations described below.

Mathematics

1 answer:

emmasim [6.3K]3 years ago

6 0

Answer:

8x10+m

Step-by-step explanation:

because of PEMDAS you multiply the 8x10 1st then add the product to m

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Last one, please help!: :)

zalisa [80]

Answer:

I think A is right....

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7 0

2 years ago

A 60 inch board is to be cut into three peices so that the second peice is four times as long as the first peice and the third p

Lostsunrise [7]

Answer:

The first piece is 6 inches, the second piece is 24 inches, and the third piece is 30 inches

Step-by-step explanation:

Since the second piece is 4 times longer than the first one, it will be represented by 4x.

The third piece is 5 times as long as the first one, so it will be represented by 5x.

Create an equation adding up the 3 x values up to 60:

x + 4x + 5x = 60

Add like terms and solve for x:

10x = 60

x = 6

So, the first piece is 6 inches.

Then, plug in 6 for x to find the lengths of the second and third pieces.

4(6)

= 24

The second piece is 24 inches

5(6)

= 30

The third piece is 30 inches

So, the first piece is 6 inches, the second piece is 24 inches, and the third piece is 30 inches

6 0

3 years ago

This is really confusing me:<br> Simplify so that your answers contain only positive exponents.

xxTIMURxx [149]

Answer:

see below

Step-by-step explanation:

For simplifying expressions of this sort, there are four rules of exponents that come into play;

$a^ba^c=a^{b+c}\\\\(ab)^c=a^cb^c\\\\(a^b)^c=a^{bc}\\\\\dfrac{1}{a^b}=a^{-b}\ \quad\text{which means}\quad a^b=\dfrac{1}{a^{-b}}$

I find it convenient to eliminate the fractions by adding the exponents, then rewrite any negative exponents as denominator factors.

$23. \quad\dfrac{1}{x^{-2}}=x^2\\\\24. \quad\dfrac{mn}{m^2n^3}=m^{1-2}n^{1-3}=m^{-1}n^{-2}=\dfrac{1}{mn^2}\\\\25. \quad\dfrac{k^{-2}}{k^{-3}}=k^{-2-(-3)}=k\\\\26. \quad\left(\dfrac{m^2}{n^3}\right)^3=\dfrac{m^{2\cdot 3}}{n^{3\cdot 3}}=\dfrac{m^6}{n^9}\\\\27. \quad\dfrac{x^2y^3z^4}{x^{-3}y^{-4}z^{-5}}=x^{2-(-3)}y^{3-(-4)}z^{4-(-5)}=x^5y^7z^9$