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noname [10]
3 years ago
10

How to do do trinomials in a easy way

Mathematics
1 answer:
Savatey [412]3 years ago
7 0
Multiply the First<span> terms
</span>Multiply the Outside<span> terms
</span>Multiply the Inside<span> term
</span>Multiply the Last<span> terms
</span>Simplify

Understand factoring.

Write a space for the answer in FOIL form.<span>
Don't write + or - between the blank terms yet, since we don't know which it will be.
</span>
<span>Fill out the First terms.
</span>
<span>Use factoring to guess at the Last terms.
</span>
<span>Test which possibilities work with Outside and Inside multiplication.
</span>
<span>Use simple factoring to make more complicated problems easier.
</span>
<span>Look for trickier factors.
</span>
<span>Solve problems with a number in front of the x^2.
</span>
<span>Use substitution for higher-degree trinomials.
</span>
Check for prime numbers.

Check to see if the trinomial is a perfect square.

<span>Check whether no solution exists.
</span>
If both binomials have the same variables to the same powers, then it is true. In general, multiplying binomials gives four terms, one corresponding to each letter of the FOIL acronym. So, you only get a trinomial when the O and I terms combine.
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Answer:

D. (-3, 2)

Step-by-step explanation:

The original point is (3, -2)

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The rule for reflecting across the y-axis is (x, y) -> (-x, y)

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Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?
mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem  

we know that  

If m∠E = m∠Y and m∠F = m∠X  

then  

Triangles EFG and YXZ are similar by AA Similarity Theorem  

Remember that  

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent  

In this problem  

The corresponding sides are  

FE and XY  

EG and YZ  

GF and ZX  

so therefore  

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.  

Suppose the ΔABC is a right triangle and ∠A is 90°.  

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!  

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.  

From the figure in the attachment , we can conclude that:  

m∠E = m∠Y  

m∠F= m∠X  

m∠G = m∠Z  

∴ ΔEFG ~ ΔYXZ  ( ΔEFG is similar to ΔYXZ )    

Because of the similarity , then:  

FE : XY = EG : YZ = GF : ZX  

Conclusion:

ΔFG is similar to ΔYXZ.  

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:    

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

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