Answer:
Volume = 14,836.5 cubic inches
Step-by-step explanation:
Cylinder not shown but information given. So we will calculate the volume.
Volume of Cylinder is given by the formula:
Where
V is the volume
r is the radius (HALF of DIAMETER)
h is the height
It is given in the problem,
Height is 21
h = 21
and
half the diamter (aka radius) is 15
r = 15
Substituting into formula and using 3.14 for 
, we get the volume:
Hence, the volume is:
Volume = 14,836.5 cubic inches
The result is a line perpendicular to y=3x-2
This line has the following equation: y =mx + b, where m = slope
Remember that the product of the slopes of two perpendicular lines is always = -1 (or in other term one is the reciprocal inverse of the other) so the
first slope = 3 and the sope perpendicular to 3 will be - 1/3.
Then the new equation is y = - 1/3(x) + b
How to calculate b? This line passes through (6, 8), that
means (x=6 and y=8) . Plug these values in y = -1/3 (x)+b:3
8=(-1/3)(6) + b;
8= - 2 + b and b = 10
Te final equation is y = - 1/3.x+10 (answer A)
Answer: The initial volume is 593.76mL
Step-by-step explanation:
As you do not say anithing about the pressure, i guess that the pressure remains constant.
If the gas is an ideal gas, we have:
P*V = n*R*T
where P is pressure, n is number of moles and R is a constant.
Now, initially we have:
P*Vi = n*R*315°C
finally we have:
P*825mL = n*R*452°C
Now we can take the quiotient of those two equations and get:
(P*Vi)/(P*852mL) = (n*R*315°C)/( n*R*452°C)
Now we have:
Vi/852mL = 315/452
Vi = (315/452)*852mL = 593.76mL
So when we expand the gas at constant pressure, we increase the temperature.
Answer:
A = π · (r²)
Step-by-step explanation:
π · r² is the area of a circle.
While π · r² · h can also give you the radius, it can only do so for the Volume 
, not the Area 
.
doesn't really apply for a circular object, as it requires the length and width. For circular objects, both are equal to the diameter of the object, and 2² · r² · h does not equal the Volume.
π · r³ seems awfully like the volume of a sphere, but there's something missing. The true volume of a sphere is 
· π · r³, not π · r³.
only applies for triangles.
4qr+20g-11q hopefully this would help you
