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3 years ago

–4(x – 26) = –200 Solve for x

Mathematics

2 answers:

hjlf3 years ago

5 0

Answer:

x = 76

Step-by-step explanation:

If you want to solve for x you need to isolate it. So try to get rid of everything on the left side of the equation in order to isolate x.

First, in order to get rid of the 4, you want to want to divide the left side by -4. This cancels out the 4.

If you divide the left side then you have to divide the right side. (Whatever you do to one side of the equation you must do to the other side)

-4(x - 26) = -200

[-4(x-26) ] / 4 =[ -200] / 4

x -26 = -200/-4

x - 26 = 50

Then you need to add the 26 to cancel it out in order to isolate x, (you have to do the opposite operation in order to cancel it out) .

x -26 + 26 = 50 + 26

x = 76

adell [148]3 years ago

3 0

Answer:

Step-by-step explanation:

–4(x – 26) = –200

–4x + 104 = –200

–104 –104

–4x/–4 = –304/–4

x = 76

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You go to an arcade and purchase a card with game credits. After playing 5 games you have 33 credits left. You play 4 more games

Amanda [17]

Answer:

$y=-3x+48$

Step-by-step explanation:

We will use slope-intercept form of equation to write our equation. The equation of a line in slope-intercept form is: $y=mx+b$ , where m= Slope of the line, b= y-intercept.

To write the equation that represents the number of credits y on the cards after x games, we will find slope of our line.

We have been given that after playing 5 games we have 33 credits left. We play 4 more games and we have 21 credits left. So our points will be (5,33) and (9,21).

Let us substitute coordinates of our both given points in slope formula: $m=\frac{y_2-y_1}{x_2-x_1}$ ,

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Now let us substitute m=-3 and coordinates of point (5,33) in slope intercept form of equation to find y-intercept.

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$33=-15+b$

$33+15=b$

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$y=-3x+48$

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3 years ago

Plz Help

GenaCL600 [577]

Begin by factoring 2 out of 2x^2 - 2x - 12 equals 0:

2(x^2 - x - 6) = 0

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This results in x = 3 and x = -2. The equation is true for these two x-values.

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3 years ago

x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco

igomit [66]

Answer:

$x=-cos(t)+2sin(t)$

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

$a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0$

Will have a characteristic equation of the form:

$a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0$

Where solutions $r_1,r_2...,r_n$ are the roots from which the general solution can be found.

For real roots the solution is given by:

$y(t)=c_1e^{r_1t} +c_2e^{r_2t}$

For real repeated roots the solution is given by:

$y(t)=c_1e^{rt} +c_2te^{rt}$

For complex roots the solution is given by:

$y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)$

Where:

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Let's find the solution for $x''+x=0$ using the previous information:

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As you can see, is the same solution provided by the problem.

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Evaluating the initial conditions:

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And

$x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2$

Now we have found the value of the constants, the solution of the second-order IVP is:

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