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monitta
3 years ago
8

Biofuels and nuclear power may prove useful as _________.

Physics
1 answer:
Papessa [141]3 years ago
5 0
As oil ,coal ,gas ,solar ,wind and water power
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hen approaching a curve, it is best to: A. Search for possible collision traps and escape paths B. Stay close to the centerline
WINSTONCH [101]

Squeezing the clutch lever to slow down is best to be done when approaching a curve and is denoted as option C.

<h3>What is Clutch?</h3>

This is a mechanical device which used in the engagement and disengagement of transmission system in a vehicle.

Slowing down will give the driver more time to maneuver the curves so as to prevent accident. This is why it is imperative to squeeze the clutch in such road condition.

Read more about Clutch here brainly.com/question/14318041

#SPJ1

8 0
2 years ago
Two long, parallel wires carry currents in the same direction. If I1 = 10 A, and I2 = 20 A, and they are d = 1.0 m apart, what i
mafiozo [28]

Answer:

The magnetic field at mid point between two parallel wires is 1.2 x 10⁻⁵ T

Explanation:

Given;

current in the first wire, I₁ = 10 A

current in the second wire, I₂ = 20 A

distance between the two wires, d = 1.0 m

Magnetic field at mid point between two parallel wires is calculated as;

B = \frac{\mu_o I_1}{2\pi r} + \frac{\mu_o I_2}{2\pi r} \\\\B =  \frac{\mu_o }{2\pi r}(I_1 +I_2)

where;

r is the midpoint between the wires, = 0.5 m

μ₀ is the permeability of free space, = 4π x 10⁻⁷

B =  \frac{\mu_o }{2\pi r}(I_1 +I_2)\\\\B =   \frac{4\pi*10^{-7} }{2\pi *0.5}(10 +20)\\\\B =  \frac{4\pi*10^{-7} *30}{2\pi *0.5}\\\\B = 1.2 *10^{-5} \ T

Therefore, the magnetic field at mid point between two parallel wires is 1.2 x 10⁻⁵ T

3 0
3 years ago
A spring-loaded toy gun is used to launch a 12.0-g plastic ball. The spring which has a spring constant of 15.0 N/m is compresse
ziro4ka [17]

Answer:

the elastic potencial energy stored when the spring is compressed x=8 cm is K(x)= 0.048 J

Explanation:

since the work is related with the force through

W=∫F dx

for a spring of constant k :

F=k*x , where F= compression force, x= compression length

then for a compression from 0 until x

W=∫F dx = ∫ k*x dx =  k ∫x dx =1/2*k*x² - 1/2*k*0² = V(x) - V(0)

since the work depends only on the final value of compression and not on the process 1/2*k*x² represents the elastic potential energy V stored in the spring, then

V(0) = 1/2*k*0² = 0  

V(x) = 1/2*k*x²

when the spring is compressed x= 8 cm = 0.08m , the elastic potencial energy is

V (x) = 1/2*k*x² = 1/2 * 15 N/m* (0.08m)² = 0.048 J

4 0
3 years ago
4cm cubed = ?m cubed
Neporo4naja [7]

Answer:

{ \rm{1 \:  {cm}^{3} =  \frac{1}{100 {}^{3} }  \:  {m}^{3}  }} \\  \\  { \rm{4 \:  {cm}^{3}  =  \frac{4}{1000000}  \:  {m}^{3} }} \\  \\ { \boxed{ \rm{ = 0.000004 \:  {m}^{3} }}}

5 0
2 years ago
The carts are moving on a level, frictionless track. After the collision all three carts stick together. Find the speed of the c
yaroslaw [1]

Answer:

0.13 m/s

Explanation:

Unfortunately, I don't have an explanation but I guessed the correct answer.

3 0
3 years ago
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