A car starts from rest and accelerates at 9 m/s². After 240 m. the final speed is 66 m/s.
<h3>What is Uniformly Accelerated Motion?</h3>
Uniformly Accelerated Motion is the motion of an object where the acceleration is constant.
A car starts from rest, that is, its initial speed is 0 m/s. It accelerates at 9 m/s². We can find the final speed after 240 m using the following kinematic equation.
v² = u² + 2 × a × s
v² = (0 m/s)² + 2 × (9 m/s²) × 240 m
v = 66 m/s
where,
- v is the final speed.
- u is the initial speed.
- a is the acceleration.
- s is the displacement.
A car starts from rest and accelerates at 9 m/s². After 240 m. the final speed is 66 m/s.
Learn more about Uniformly Accelerated Motion here: brainly.com/question/10178440
Globalization concerns many workers because companies will tend to seek lower costs by outsourcing labor.
Answer:
Number of days needed = 57
Explanation:
Depth of well = 115 feet
Distance traveled in day = 3 feet up
Distance traveled in night = 1 feet down.
Total displacement in 1 day = 3 - 1 = 2 feet up
When the snail reaches 112 feet up, the next 3 feet up motion on day will make it reach the top.

After 56 days the displacement of snail is 112 feet.
On the next day it moves up by 3 feet and reaches out of well.
Number of days needed = 57
Answer:
True
Explanation:
If a thin, spherical, conducting shell carries a negative charge, We expect the excess electrons to mutually repel one another, and, thereby, become uniformly distributed over the surface of the shell. The electric field-lines produced outside such a charge distribution point towards the surface of the conductor, and end on the excess electrons. Moreover, the field-lines are normal to the surface of the conductor. This must be the case, otherwise the electric field would have a component parallel to the conducting surface. Since the excess electrons are free to move through the conductor, any parallel component of the field would cause a redistribution of the charges on the shell. This process will only cease when the parallel component has been reduced to zero over the whole surface of the shell
According to Gauss law
∅ = EA =-Q/∈₀
Where ∅ is the electric flux through the gaussian surface and E is the electric field strength
If the gaussian surface encloses no charge, since all of the charge lies on the shell, so it follows from Gauss' law, and symmetry, that the electric field inside the shell is zero. In fact, the electric field inside any closed hollow conductor is zero