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lubasha [3.4K]
2 years ago
15

If the pendulum took longer to complete one oscillation, how would the graph change?

Physics
2 answers:
pickupchik [31]2 years ago
7 0

We don't know what kind of graph it is.

For example, it might be a graph of the pendulum's distance from center,

angle from center, speed, acceleration, total distance swung since it was

started, mass, weight, temperature, etc.


If the graph shows the pendulum's distance from center, angle from center,

speed, or acceleration, then the graph will look like a wave, with the period

of the wave being the period of the pendulum's oscillation. If the pendulum

took longer to complete one oscillation, that means its PERIOD increased,

and the distance between the peaks of the graph would be longer.


If it was a graph of total distance the pendulum swung since it was started,

the graph wouldn't look like a wave, just a steadily rising wiggle line. If the

pendulum took longer to complete one oscillation, the wiggles in the line

would be farther apart, and the average slope of any large section of the

line would be less.


If it was a graph of the pendulum's mass, weight, temperature, cost, etc.,

then the graph would be a horizontal line, and nothing that might change

the period of oscillation would have any effect on the graph.

posledela2 years ago
7 0

The distance between peaks would be longer


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ANSWER:

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3 years ago
An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s . Suppose that
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Answer:

0.0241875 m

Explanation:

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Time taken = 0.3 seconds

In this system as the linear momentum is conserved

m_1v_1+m_2v_2=0\\\Rightarrow v_1=-\frac{m_2v_2}{m_1}\\\Rightarrow v_1=-\frac{0.43\times 15}{80}\\\Rightarrow v_1=0.080625\ m/s

Assuming this velocity is constant

Distance=Velocity\times Time\\\Rightarrow Distance=0.080625\times 0.3\\\Rightarrow Distance=0.0241875\ m

The distance the quarterback will move in the horizontal direction is 0.0241875 m

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2 years ago
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Diano4ka-milaya [45]
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2 years ago
A cylinder with rotational inertia I₁ = 2.4 kg · m² rotates clockwise about a vertical axis through its center with angular spee
miv72 [106K]

Answers :

Explanation:

Given that.

First cylinder data

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Second cylinder data

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angular speed ω₂ = 7.0 rad/s.

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So, the cylinder couple and move together with the same angular speed

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The combine angular speed of the cylinder is 6.22 rad/s

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mars1129 [50]

Answer:

I hope the answer helps you

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2 years ago
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