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Ostrovityanka [42]
3 years ago
12

What is the value of 2 in 0.812 writen as a fraction

Mathematics
2 answers:
Zanzabum3 years ago
5 0
Thousandths place hope e I helped
anzhelika [568]3 years ago
4 0
The 2 is in the thousands place so it would be 2/1000
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Rectangle 30 ft wide and 70 feet long. How long would diagonal corners be?
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Answer:

around 76.16

Step-by-step explanation:

30 squared + 70 squared = 5800

square root of 5800 = 76.16

a squared + b squared = c squared

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Solve for x.<br><br> −8 = 2/3x<br><br> A) −6 <br> B) −9 <br> C) −12 <br> D) −24
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What is the measure of the largest angle of a triangle whose measures are in the ratio 2:3:4
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6 0
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Determine the equation of the circle with centre (-3;5) and passing through a point (2;-9)
UNO [17]

Therefore, the equation of circle is: (x+3)^{2}+(y+5)^{2} = 100

<h3><u>What is a circle?</u></h3>
  • All points in a plane that are at a specific distance from a specific point, the center, form a circle. In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant.
  • The radius of a circle is the separation between any point on the circle and its center.
  • The radius must typically be a positive integer. Except when otherwise specified, this article discusses circles in Euclidean geometry, namely the Euclidean plane.
  • A circle, specifically, is a straightforward closed curve that separates the plane into its inner and exterior.

Here we know that(h,k) = (-3,5)but we are not given the radius.

However, we can find the radius by using the distance formula.

\sqrt{x^{2} +y^{2} }, where x=x_{1} -x_{2} and y=y_{1} -y_{2}

Putting the values, we get:

\sqrt{8^{2} +6^{2} }

The radius comes out to be:

r=10

An equation of the circle with center (h,k) and radius r is

(x-h)^{2} +(y-k)^{2} = r^{2}

Now, substituting the values, we get:

(x--3)^{2} +(y-5)^{2} = 10^{2}

Therefore, the equation of circle is:

(x+3)^{2}+(y+5)^{2} = 100

Know more about circles with the help of the given link:

brainly.com/question/10618691

#SPJ4

7 0
2 years ago
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