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1 year ago

What is the end behavior of the function f(x)=−1/4x^2?

Mathematics

1 answer:

ki77a [65]1 year ago

3 0

Answer:

As x approaches infinity, f(x) approaches negative infinity

As x approaches negative infinity, f(x) approaches negative infinity

Step-by-step explanation:

Because the function goes in the downward direction on both sides, it would be negative infinity for both.

It's basically saying, as the x values go towards the positives, the y values go towards the negatives

and as the x values go towards the negatives, the y values go towards the negatives.

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Help please<br> what is<br>

dsp73

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
$f(x) = |x|+5$
$= > x = -5$ (1)

$= > x = 5$ (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. $R{f(x)eR [f(x) < 5}$ is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

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2 years ago

Hi! im alex, just answer these easy questions and recive your points <3

Delvig [45]

Answer

106 sio so you multiply first

1+1+2+3+4+5+6×15

1+1+2+3+4+5+90

then you add all of them then it will be 106

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3 years ago

A room has a cathedral ceiling. If the walls in the room are 10 feet high and the ceiling is 18 feet high in the center of the r

9966 [12]

Check the picture below

notice, the run is half 35

recall slope = rise/run

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3 years ago

Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?

serious [3.7K]

Answer:

c) 6x + y = -52 is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form : y = mx + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 : -x + 6y = -12

or, 6y = -12 + x

or, y = (x/6) - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2 to be perpendicular:

Check for each equation:

a. x + 6y = -67 ⇒ 6y = -67 - x

or, y = (-x/6) - (67/6) ⇒Slope of line 2 = (-1/6)

but $\frac{1}{6} \times \frac{-1}{6} \neq -1$

b. x - 6y = -52 ⇒ -6y = -52 - x

or, y = (x/6) + (52/6) ⇒Slope of line 2 = (1/6)

but $\frac{1}{6} \times \frac{1}{6} \neq -1$

c. 6x + y = -52

or, y =y = -52 - 6x ⇒Slope of line 2 = (-6)

$\frac{1}{6} \times (-6) = -1$

Hence, 6x + y = -52 is required equation 2.

d. 6x - y = 52 ⇒ -y = 52 - 6x

or, y = 6x - 52 ⇒Slope of line 2 = (6)

but $\frac{1}{6} \times 6 \neq -1$

Hence, 6x + y = -52 is the only required equation .

3 0

3 years ago

Read 2 more answers

A= LW For W<br><br> HELP ME!?!

madam [21]

W=A\L

Divide L from both sides

The L in the right cancels out

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3 years ago