Answer:
you forgot to add the figure
Step-by-step explanation:
The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
Read more about surface area at
brainly.com/question/76387
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Answer:
<h2>
23 cars</h2>
Step-by-step explanation:
total number of cars: x
the total number of axles: 46
and the number of axles installed per car: 2
2 axles in each car, then total instaled axles: 2•x
2•x = 46
x = 46÷2
x = 23
Answer:
(fоg)(x) = x
Step-by-step explanation:
f(x) = (x-1)/3
g(x)=3x+1
(fоg)(x) = f(g(x)) = ((3x+1)-1) / 3 = 3x / 3 = x
