Which of the following sets contains all roots of the polynomial f(x)=2x^3+3x^2-3x-2?
1 answer:
Answer:
C
Step-by-step explanation:
Given
f(x) = 2x³ + 3x² - 3x - 2
Note that
f(1) = 2 + 3 - 3 - 2 = 0 , thus
(x - 1) is a factor
Dividing f(x) by (x - 1) gives
f(x) = (x - 1)(2x² + 5x + 2) = (x - 1)(x + 2)(2x + 1)
To find the roots equate f(x) to zero, that is
(x - 1)(x + 2)(2x + 1) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
x + 2 = 0 ⇒ x = - 2
2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = -
The solution set is therefore
{ - 2, - , 1 } → C
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Using the distance formula, , what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?
Using the points given, plug them into the equation.
Plug this into a calculator and you get 6.32455532
Since you only need it up to the tenth (0.1), round up 6.32
<em>Five or more, let it soar. Four or less, let it rest.</em>
Since two is lower than four, we drop it.
Therefore, the distance between points (-2, 2) and (4, 4) is 6.3
Hope this helps ^w^