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3 years ago

HELP PLEASE if it’s incorrect why

Mathematics

1 answer:

Vinil7 [7]3 years ago

6 0

It is incorrect because those dividers prevent it from being a negative. Therefore it is wrong.

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Find the area of the shaded sector. Leave your answer in terms of π.

kozerog [31]

Answer:

18π ft^2

Step-by-step explanation:

The area of the circle is

pi *r^2

pi * 12^2

144pi

The part that is shaded is 45 degrees

An entire circle is 360 degrees

The fraction that is shaded is 45/360 = 1/8

Multiply the area by the fraction that is shaded

1/8 * 144 pi

18 pi

5 0

3 years ago

Read 2 more answers

Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4

arsen [322]

we are given

$R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k$

now, we can find x , y and z components

$x=cos(8t),y=sin(8t),z=8ln(cos(t))$

Arc length calculation:

we can use formula

$L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt$

$x'=-8sin(8t),y=8cos(8t),z=-8tan(t)$

now, we can plug these values

$L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt$

now, we can simplify it

$L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt$

$L=\int _0^{\frac{\pi }{4}}8sec(t) dt$

now, we can solve integral

$\int \:8\sec \left(t\right)dt$

$=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|$

now, we can plug bounds

and we get

$=8\ln \left(\sqrt{2}+1\right)-0$

so,

$L=8\ln \left(1+\sqrt{2}\right)$ ..............Answer

5 0

3 years ago

One ball is drawn from a bag containing 4 red balls numbered 1–4 and 10 white balls numbered 5–14. Find the following probabilit

omeli [17]

Step-by-step explanation:

9 in total numbers can't be divided by 3...

therefore your probability will be = 9/14

= 0.64

8 0

3 years ago

Equation of a line that passes through points (4,2) and (-2,-4)?

IRINA_888 [86]

Hello there!

Step-by-step explanation:

<h2>Lesson: Exploring Slope and Slope-intercept form</h2>

Slope formula: $m=\frac{Y^2-Y^1}{X^2-X^1}$

Rise/run

$\frac{rise}{run}$

$m=\frac{(-4)-2=-6}{(-2)-4=-6}=\frac{6}{6}=1$

<em><u>Therefore, the slope is 1.</u></em>

<em><u>Answer: 1</u></em>

Hope this helps!

Thanks!

-Charlie

6 0

3 years ago

At 0°C, the volume of a gas is 22 liters. For each degree the temperature T (in degrees Celsius) increases, the volume V (in lit

Leto [7]

V=(2/25)x + 22
when x=0 the volume is equal to 22.
when x=1 the volume is equal to 22 +2/25
when x=2 the volume is equal to 22+2/25*2, etc.
So, each degree increases in temperature, the volume is increasing by 2/25 cubic liters.
(Hope this helps you! Feel free to message me for any additional question. :) Have a nice day!)

4 0

4 years ago