Find the value in Australian dollars for each exchange rate.
<span>1st exchange rate: </span>
<span>14000/6.21= $2254.43 </span>
<span>2nd exchange rate: </span>
<span>14000/6.37= $2197.80 </span>
<span>Find the difference between the two: </span>
<span>$2254.43 - $2197.80 = $56.63 </span>
Since the first value is greater than your second one Aggie lost money and your answer is <span>It decreases by $56.63.</span>
Answer:
116
Step-by-step explanation:
36+28=64
180-64=116
Answer:
In general, number of proper subsets of a given set = 2m - 1, where m is the number of elements.
Answer:
The positive value of
will result in exactly one real root is approximately 0.028.
Step-by-step explanation:
Let
, roots are those values of
so that
. That is:
(1)
Roots are determined analytically by the Quadratic Formula:
![t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B69%5Cpm%20%5Csqrt%7B4761-6182720%5Ccdot%20k%5E%7B2%7D%20%7D%7D%7B38642%7D)
![t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }](https://tex.z-dn.net/?f=t%20%3D%20%5Cfrac%7B69%7D%7B38642%7D%20%5Cpm%20%5Csqrt%7B%5Cfrac%7B4761%7D%7B1493204164%7D-%5Cfrac%7B80%5Ccdot%20k%5E%7B2%7D%7D%7B19321%7D%20%20%7D)
The smaller root is
, and the larger root is
.
has one real root when
. Then, we solve the discriminant for
:
![\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}](https://tex.z-dn.net/?f=%5Cfrac%7B80%5Ccdot%20k%5E%7B2%7D%7D%7B19321%7D%20%3D%20%5Cfrac%7B4761%7D%7B1493204164%7D)
![k \approx \pm 0.028](https://tex.z-dn.net/?f=k%20%5Capprox%20%5Cpm%200.028)
The positive value of
will result in exactly one real root is approximately 0.028.
Answer: the answer is 6.38
Step-by-step explanation: You have to divide 25.40/4 you can use base ten blocks or draw it out or just divide that is how i got the answer!