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Veronika [31]
3 years ago
14

Tan2(θ) − 3 = 0 Find all solutions for the given equation.

Mathematics
1 answer:
kondaur [170]3 years ago
4 0
Hello :
tan²(θ) = 3.. equi : tan(θ) = √3  or tan(θ) = -√3
1 ) tan(θ) = √3
tan(θ) = tan(<span>π/3)
</span>θ = π/3 +kπ  k in Z
2)tan(θ) = -√3
tan(θ) = tan(-π/3)
θ = -π/3 +kπ  k in Z


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Answer:

FIRST EXPRESSION:

-  If b=-3, the value of 4b(b+1) is  24

-  If b=-2, the value of 4b(b+1) is  8

- If b=10, the value of 4b(b+1) is  440

 SECOND EXPRESSION:

-  If b=-3, the value of (2b+7)(2b-8)) is  -14

-  If b=-2, the value of (2b+7)(2b-8)) is  -36

- If b=10, the value of (2b+7)(2b-8)) is  324

Yes, for any value of "b" the value of the first expression is greater than the value of the second expression.

Step-by-step explanation:

Substitute the given values of "b" into each expression and evaluate.

- For the first expression 4b(b+1), you get:

If b=-3 → 4(-3)(-3+1)=24

If b=-2 → 4(-2)(-2+1)=8

 If b=10 → 4(10)(10+1)=440

 - For the second expression (2b+7)(2b-8)), you get:

If b=-3 → (2(-3)+7)(2(-3)-8)=-14

If b=-2 → (2(-2)+7)(2(-2)-8)=-36

 If b=10 → (2(10)+7)(2(10)-8)=324

You can observe that for any value of "b" the value of the first expression is greater than the value of the second expression.

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